javascript - 带有逗号分隔项的多个值的 Jquery-ui-autocomplete 不起作用

Question

我正在研究 jquery-ui-autocomplete ，但我的要求是使用逗号分隔的多个值，我编写的代码仅适用于单个值

1) when search/autocomplate  in text box it should get username and id of that user but id not show to front end just binded with user names
2)selected usernames show in text box with multiple values using comma separated (currently it is working for single user only comma is appending but multiple values not)
3) whenever selected any username  id associated with that user append into hidden field  " name='hidden_id[]'  "

<input type="text" name="search_val" class="form-control search_val"/>

<input type="hidden" name="hidden_id[]" class="hidden_id" value=""/>

<script>
$(function () {
    $(document).ready(function () {
        function split(val) {
            return val.split(/,\s*/);
        }
        function extractLast(term) {
            return split(term).pop();
        }
        $(".search_asset").autocomplete({
            source: function (request, response) {
                $.ajax({
                    url: "<?php echo SITE_URL . 'ajax/get_users'; ?>",
                    dataType: "json",
                    data: {
                        term: request.term, request: 1
                    },
                    success: function (data) {
                        response(data);
                    }
                });
            },

            select: function (event, ui) {
                var terms = split(this.value);
                // remove the current input
                terms.pop();
                // add the selected item
                terms.push(ui.item.value);
                // add placeholder to get the comma-and-space at the end
                terms.push("");
                this.value = terms.join(",");
                return false;
            }
        });

    });


    public function get_users() {
        $term = $_GET['term'];
        $result = $this -> db -> query("select userid,username from users WHERE username LIKE '%".$term."%' ") -> result();
        if (count($result) > 0) {
            foreach($result as $row)
            $arr_result[] = $row -> username;
            $arr_result[] = $row -> userid;
            echo json_encode($arr_result);
        }
    }
});

标签： javascriptjqueryautocomplete

Answer 1

只需对您的代码进行一些小改动，然后试试这对我来说效果很好。

 $( function() {        
        $( ".search_val" ).autocomplete({
            source: function( request, response ) {
                
                var searchText = extractLast(request.term);
                $.ajax({
                    url: "<?php echo SITE_URL . 'ajax/get_users'; ?>",
                    type: 'get',
                    dataType: "json",
                    data: {
                        search: searchText
                    },
                    success: function( data ) {
                        response( data );
                    }
                });
            },focus: function() {                
                return false;
            },
            select: function( event, ui ) {
                var terms = split( $('.search_val').val() );
                
                terms.pop();               

               if(duplicate($('.search_val').val(), ui.item.label)){
                terms.push( ui.item.label );
                
                terms.push( "" );
                $('.search_val').val(terms.join( ", " ));            
                 }
                return false;
            }
           
        });
    });

    function split( val ) {
      return val.split( /,\s*/ );
    }
    function extractLast( term ) {
      return split( term ).pop();
    }
function duplicate(f,s){
  if( f.match(new RegExp("(?:^|,)"+s+"(?:,|$)"))) {
    	return false;
   }else{
	   return true;
  }
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script
  src="https://cdnjs.cloudflare.com/ajax/libs/jqueryui/1.12.1/jquery-ui.min.js"></script>

<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jqueryui/1.12.1/jquery-ui.min.css">
  <input type="text" name="search_val" class="form-control search_val"/>

更改您的 php 代码

while($row = mysqli_fetch_array($result) ){ $response[] = > array("value"=>$row['userid'],"label"=>$row['username']); }

回声 json_encode($response);