python-3.x - Python fonttools：检查字体是否支持多代码点表情符号

Question

我正在尝试检查字体是否具有多代码点表情符号的字形，例如 Python 3.x 中的“‍♂️”、“‍”或“”。

对于像 "" 或 "" 这样的单个代码点表情符号，我可以使用 Python 通过以下代码验证它们的支持fonttols：

from fontTools.ttLib import TTFont

def __isEmojiSupportedByFont(emoji: str) -> bool:
    font = TTFont(r"C:\Windows\Fonts\seguiemj.ttf")
    emojiCodepoint = ord(str) # Only works for single codepoint emoji
    for table in font['cmap'].tables:
        for char_code, glyph_name in table.cmap.items():
            if char_code == emojiCodepoint:
                return True
    return False

我该如何为多代码点表情符号执行此操作，因为其中cmp只有单个代码点表情符号？

标签： python-3.xemojipython-unicodecodepoint

Answer 1

要检查多代码点表情符号，我必须“查询”GSUB 查找列表。

检查python中的字体是否支持表情符号的更简单方法是使用HarfBuzz或更准确的harfpy。

我想出的解决方案是：

from uharfbuzz import Face, Font, Buffer, ot_font_set_funcs, shape

def __isEmojiSupportedByFont(self, emoji: str) -> bool:
    # Load font:
    with open(r"C:\Windows\Fonts\seguiemj.ttf", 'rb') as fontfile:
        self.fontdata = fontfile.read()

    # Load font (has to be done for call):
    face = Face(self.fontdata)
    font = Font(face)
    upem = face.upem
    font.scale = (upem, upem)
    ot_font_set_funcs(font)

    # Create text buffer:
    buf = Buffer()
    buf.add_str(emoji)
    buf.guess_segment_properties()

    # Shape text:
    features = {"kern": True, "liga": True}
    shape(font, buf, features)

    # Remove all variant selectors:
    while len(infos) > 0 and infos[-1].codepoint == 3:
        infos = infos[:-1]

    # Filter empty:
    if len(infos) <= 0:
        return False

    # Remove uncombined, ending with skin tone like "":
    lastCp = infos[-1].codepoint
    if lastCp == 1076 or lastCp == 1079 or lastCp == 1082 or lastCp == 1085 or lastCp == 1088:
        return False

    # If there is a code point 0 or 3 => Emoji not fully supported by font:
    return all(info.codepoint != 0 and info.codepoint != 3 for info in infos)

感谢GitHub/fonttols上的khaledhosny和justvanrossum！