首页 > 解决方案 > Bash 将命令输出与字符串进行比较

问题描述

输出是一样的,而且总是回显need to pull$text如果我在条件下删除引号,if则会引发too many arguments错误。

var="$(git status -uno)" && 

text="On branch master Your branch is up-to-date with 'origin/master'. nothing to commit (use -u to show untracked files)"; 

echo  $var; 
echo  $text; 
if [ "$var" = "$text" ]; then
    echo "Up-to-date"
else
    echo "need to pull"
fi

标签: bashgit-bash

解决方案


=~对于bash 正则表达式,最好这样做:

#!/bin/bash

var="$(git status -uno)" 

if [[ $var =~ "nothing to commit" ]]; then
    echo "Up-to-date"
else
    echo "need to pull"
fi

或者

#!/bin/bash

var="$(git status -uno)" 

if [[ $var == *nothing\ to\ commit* ]]; then
    echo "Up-to-date"
else
    echo "need to pull"
fi

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