首页 > 解决方案 > 创建一个抽象逻辑的组件(从现有代码)

问题描述

我创建了这段代码:

import React from 'react'
import { range } from 'lodash'

const DIV_NUMBER = 5

export default class App extends React.Component {
  constructor(props) {
    super(props)
    this.divs = []
  }

  handleScroll = divIdx => () => {
    const divRef = this.divs[divIdx]
    const left = divRef.scrollLeft
    const top = divRef.scrollTop
    this.divs.forEach(div => (div.scrollLeft = left))
    this.divs.forEach(div => (div.scrollTop = top))
  }

  render() {
    return (
      <div style={{ border: '1px solid tomato' }}>
        {range(DIV_NUMBER).map(i => {
          return (
            <div
              key={i}
              ref={divElem => (this.divs[i] = divElem)}
              onScroll={this.handleScroll(i)}
              style={{
                width: 300,
                height: 100,
                margin: '2px',
                overflow: 'auto',
                border: '1px solid black',
              }}
            >
              <div
                style={{
                  width: 500,
                  height: 400,
                }}
              >
                Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor
                incididunt ut labore et dolore magna aliqua. Scelerisque eu ultrices vitae auctor eu
                augue ut lectus. In fermentum et sollicitudin ac orci. Velit sed ullamcorper morbi
                tincidunt ornare. Auctor eu augue ut lectus arcu bibendum. Non nisi est sit amet.
                Facilisis magna etiam tempor orci eu lobortis. Et tortor at risus viverra adipiscing
                at in tellus integer. Lacus luctus accumsan tortor posuere ac ut consequat semper
                viverra. Fermentum dui faucibus in ornare quam viverra orci sagittis. Porttitor eget
                dolor morbi non. Pulvinar pellentesque habitant morbi tristique senectus et.
                Tincidunt eget nullam non nisi est sit amet facilisis magna. Purus semper eget duis
                at tellus at urna condimentum. Ipsum dolor sit amet consectetur adipiscing. Sit amet
                aliquam id diam maecenas ultricies mi eget mauris. Faucibus scelerisque eleifend
                donec pretium vulputate sapien nec sagittis. Tristique senectus et netus et
                malesuada fames ac turpis. Egestas integer eget aliquet nibh. Enim ut tellus
                elementum sagittis vitae. Urna condimentum mattis pellentesque id nibh tortor id
                aliquet. Magna eget est lorem ipsum dolor. Felis imperdiet proin fermentum leo vel
                orci porta. Eget egestas purus viverra accumsan in nisl nisi. Adipiscing commodo
                elit at imperdiet. Facilisis magna etiam tempor orci eu lobortis. Volutpat est velit
                egestas dui id ornare arcu odio. Praesent elementum facilisis leo vel fringilla.
                Laoreet non curabitur gravida arcu ac tortor dignissim convallis aenean. Sodales ut
                etiam sit amet nisl. Turpis massa tincidunt dui ut ornare. Viverra mauris in aliquam
                sem fringilla ut morbi tincidunt augue.
              </div>
            </div>
          )
        })}
      </div>
    )
  }
}

有用。它创建了 5 个 div 元素,滚动其中一个,所有 div 滚动在一起。我使用 React 引用来做到这一点。

我现在想做的是创建一个抽象这个逻辑的组件。

我想象这样的事情:

<ScrollDivs>
  {range(DIV_NUMBER).map(i => {
    return (
      <div
        key={i}
        style={{
          width: 500,
          height: 400,
        }}
      >
        all the text...
      </div>
    )
  })}
</ScrollDivs>

ScrollDivs所以一个处理逻辑的神奇组件。使用这个组件的人不用担心它是怎么做的,他只需要在这个组件内部包装想要能够一起滚动的 div 即可。

我能怎么做?我不知道从哪里开始。

任何帮助表示赞赏

标签: reactjsscrollcomponentsrefactoring

解决方案


React.Children.map可以帮助您进行迭代,props.childrenReact.cloneElement可以帮助将新道具传递给孩子:

export default class ScrollDivsSync extends React.Component {
  divs = [];

  handleScroll = e => {
    const { scrollTop, scrollLeft } = e.target;
    this.divs.forEach(div => {
      div.scrollLeft = scrollLeft;
      div.scrollTop = scrollTop;
    });
  };

  render() {
    const { children } = this.props;

    let i = 0;
    const enhancedChildren = React.Children.map(children, child =>
      React.cloneElement(child, {
        onScroll: this.handleScroll,
        ref: divElem => (this.divs[i++] = divElem)
      })
    );

    return enhancedChildren;
  }
}

这是带有示例的 CodeSandbox


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