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list - 如何在 AppleScript 中的两个列表之间找到相等的值？

问题描述

我正在一个内部网站上工作，该网站有一个按此顺序列出的数据列表：

Date - FirstName - Last Name
01/01/19 - demo - demo
01/01/19 - demo - demo
01/01/19 - demo - eg
01/01/20 - demo - demo

我正在尝试找出更改日期（日期选项卡）。

我为日期创建了一个列表，为名字和姓氏创建了另外两个列表，并将它们合并到最后一个列表中。

如何返回值开始更改的日期，例如

01/01/19 - 演示 - 例如：结果 01/01/19 ？

到目前为止，这是我的脚本：

set creationDate to {}
set firstName to {}
set resultList to {}
set lastName to {}
try
    repeat with counter from 1 to 1000
        tell application "Safari"
            set myValue to do JavaScript "document.getElementsByClassName('auto-date-time')[" & counter & "].innerHTML;" in current tab of window 1
        end tell
        if myValue = missing value then
            exit repeat
        else if myValue is not equal to "" then
            set the creationDate to the creationDate & myValue
        end if
    end repeat
on error
    --
end try
set listSize to count of creationDate



try
    repeat with counter from 1 to 1000
        tell application "Safari"
            set myValue to do JavaScript "document.getElementsByClassName('sortable firstName')[" & counter & "].innerHTML;" in current tab of window 1
        end tell
        if myValue = missing value then
            exit repeat
        else if myValue is not equal to "" then
            set the firstName to the firstName & myValue
        end if
    end repeat
on error
    --
end try
set listSize to count of firstName

try
    repeat with counter from 1 to 1000
        tell application "Safari"
            set myValue to do JavaScript "document.getElementsByClassName('sortable lastName')[" & counter & "].innerHTML;" in current tab of window 1
        end tell
        if myValue = missing value then
            exit repeat
        else if myValue is not equal to "" then
            set the lastName to the lastName & myValue
        end if
    end repeat
on error
    --
end try
set listSize to count of lastName

set resultList to {}
repeat with i from 1 to count creationDate
    set end of resultList to {item i of firstName, item i of lastName}
end repeat







repeat with x from 1 to count of items of creationDate
    set n to item x of firstName
    set m to item x of lastName
    set d to item x of creationDate
    if n is not equal to m then return d
end repeat

标签： listapplescript

解决方案

我找到了，只需要在列表中添加一个重复项和项目+1并使用“IF”播放

tell application "Safari" to tell document 1 to tell (do JavaScript "
    [...new Set( document.getElementsByClassName('sortable firstName') )]
    .map( x => x.innerText.trim() );") ¬
    to set firstName to every text


tell application "Safari" to tell document 1 to tell (do JavaScript "
    [...new Set( document.getElementsByClassName('sortable descending created') )]
    .map( x => x.innerText.trim() );") ¬
    to set creationDate to every text

set myLinetoSave to ""
set dateofChante to ""

set listSize to count of firstName

repeat with each from 2 to count of items of creationDate
    set itemOnMyList to item each of firstName
    set itemOnMyListFuture to item (each + 1) of firstName  
    if itemOnMyList is not equal to itemOnMyListFuture then
        set myLinetoSave to each + 1
        set dateofChante to item (each + 1) of creationDate
        return dateofChante
    end if
end repeat

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