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python - 单击“播放”时如何清除我的游戏屏幕并移动到新场景

问题描述

我不知道如何使用按钮功能将 background.jpg 覆盖在按钮上，或者在清除场景后擦除当前屏幕并将背景放回原位。

import pygame


pygame.init()


screen = pygame.display.set_mode((800, 600))
clock = pygame.time.Clock()



BLACK = (0, 0, 0)
BACKGROUND = (200, 230, 234)
WHITE = (255, 255, 255)
HOVER_COLOUR = (50, 70, 90)
# Text Variables 
FONT = pygame.font.SysFont ("Times New Norman", 60)
TEXT = FONT.render ("", True, WHITE)
background_images = pygame.image.load("background.jpg").convert()
screen.blit(background_images, [0,0])
screen.blit(TEXT, (150, 50))
# Text & Rectangles construction
text1 = FONT.render("PlAY", True, WHITE)
text2 = FONT.render("CONTROLS", True, WHITE)
text3 = FONT.render("DIFFICULTY", True, WHITE)
text4 = FONT.render("SCOREBOARD", True, WHITE)

rect1 = pygame.Rect(250,200,300,80)
rect2 = pygame.Rect(250,300,300,80)
rect3 = pygame.Rect(250,400,300,80)
rect4 = pygame.Rect(250,500,300,80)
# The button construction arry. Text and Rectangle 
buttons = [
        [text1, rect1, BACKGROUND, 1],
        [text2, rect2, BACKGROUND, 2],
        [text3, rect3, BACKGROUND, 3],
        [text4, rect4, BACKGROUND, 4],
        ]

# Function for button printing (testing)
def on_button(buttons):
        print(buttons[3])


def game_intro():
        while True:
                for event in pygame.event.get():
                        if event.type == pygame.QUIT:
                                return
                        elif event.type == pygame.MOUSEMOTION:
                                for button in buttons:
                                        # Uses collisionpoint to detect mouse position collisions
                                        if button[1].collidepoint(event.pos):
                                                # Set the button's colour to the hover colour.
                                                button[2] = HOVER_COLOUR
                                        else:
                                                # resets the colour to normal.
                                                button[2] = BACKGROUND
                        # Button Controls 
                        elif event.type == pygame.MOUSEBUTTONDOWN:
                                for button in buttons:
                                        # Uses collisionpoint to detect mouse position collisions
                                        if button[1].collidepoint(event.pos):
                                                on_button(button)
                                        if button == buttons[0]:
                                                screen.fill(0,0,0)


                # Draws the buttons with their current colours (normal & collisions)
                for text, rect, colour, button_id in buttons:
                        pygame.draw.rect(screen, colour, rect)
                        screen.blit(text, rect)

                pygame.display.flip()
                clock.tick(15)


#Run Game
game_intro()
pygame.quit()

如您所见，操作：

if button == buttons[0]:
screen.fill(0,0,0)

是我目前正在使用的。if 语句工作正常，iv 用打印操作测试了它的反馈，但我不能用 Pygame 函数工作。

标签： pythonpygame

解决方案

该问题是由

screen.fill(0,0,0)

因为第二个参数 topygame.Surface.fill()被假定为一个矩形（例如pygame.Rect），它将填充限制在特定区域。

第一个参数pygame.Surface.fill()必须是 RGB 序列、RGBA 序列或颜色索引。

所以它必须是

screen.fill( (0,0,0) )

或者

screen.fill(0)

按钮仍然是它们，因为它们在每一帧中都是连续绘制的：

for text, rect, colour, button_id in buttons:
    pygame.draw.rect(screen, colour, rect)
    screen.blit(text, rect)

play添加按下播放按钮时设置的全局状态变量 ( )。在函数中改变状态on_button，使用global语句改变globale变量的值play。根据状态绘制场景：

play = False

def on_button(buttons):
    global play 
    play = buttons[3] == 1
    print(buttons[3], play)

def game_intro():

    # [...]

    if play:
        screen.fill(0)

        # [...]            

    else: 
        for text, rect, colour, button_id in buttons:
            pygame.draw.rect(screen, colour, rect)
            screen.blit(text, rect)

    pygame.display.flip()
    clock.tick(15)

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