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python - 您如何显示具有多行不同功能的输出以彼此相邻打印？

问题描述

基本上，我的任务是模拟掷骰子并根据掷出的骰子并排打印出来。每个骰子占用 5 行，所以我需要一种方法来打印所有 5 行，然后打印出所有 5 行的另一个骰子结果。

我一直在尝试将函数转换为常规字符串的程序，但它不起作用，我还尝试将 ,end = '' 放在函数本身中，然后简单地将它们放在彼此下方，但我也没有运气. 我只在第一个骰子是 1 的情况下发布。

import random

def roll_dice():
    return random.choice(['1','2','3','4','5','6'])

def display_die1():
    print("+-------+")
    print("|       |")
    print("|   *   |")
    print("|       |")
    print("+-------+")

def display_die2():
    print("+-------+")
    print("| *     |")
    print("|       |")
    print("|     * |")
    print("+-------+")

def display_die3():
    print("+-------+")
    print("| *     |")
    print("|   *   |")
    print("|     * |")
    print("+-------+")

def display_die4():
    print("+-------+")
    print("| *   * |")
    print("|       |")
    print("| *   * |")
    print("+-------+")

def display_die5():
    print("+-------+")
    print("| *   * |")
    print("|   *   |")
    print("| *   * |")
    print("+-------+")

def display_die6():
    print("+-------+")
    print("| * * * |")
    print("|       |")
    print("| * * * |")
    print("+-------+")

def main():
    pic1, pic2, pic3, pic4, pic5, pic6 = display_die1(), display_die2(), display_die3(), display_die4(), display_die5(), display_die6()
    print(f"Craps: A Popular Dice Game")
    prompt = input(f"Press <Enter> to roll the dice.")
    if prompt == (""):
        x = roll_dice()
        y = roll_dice()
        add = int(x) + int(y)
        if x == '1':
            if y == '1':
                print(pic1, end = '')
                print(pic1)
            if y == '2':
                print(pic1, end = '')
                print(pic2)
            if y == '3':
                print(pic1, end = '')
                print(pic3)
            if y == '4':
                print(pic1, end = '')
                print(pic4)
            if y == '5':
                print(pic1, end = '')
                print(pic5)
            if y == '6':
                print(pic1, end = '')
                print(pic6)
        stopper = int(x) + int(y)
        if add == (7 or 11):
            print(f"You rolled a {add} on your first roll.")
            print(f"You win!")
        elif add == (2 or 3 or 12):
            print(f"You rolled a {add} on your first roll.")
            print(f"You lose!")
        else:
            print(f"You rolled a {add} on your first roll.")
            print(f"\nThat's your point. Roll it again before you roll a 7 and lose!")
            while add != (7 or stopper):
                proceed = input(f"\nPress <Enter> to roll the dice.")
                if proceed == (""):                
                    x = roll_dice()
                    y = roll_dice()
                    add = int(x) + int(y)
                    if (add == 7):
                        print(f"You rolled a 7.")
                        print(f"You lose!")
                        break
                    elif (add == stopper):
                        print(f"You rolled a {stopper}.")
                        print(f"You win!")
                        break
                    else:
                        print(f"You rolled a {add}")

main()

我希望输出是两个骰子并排显示，中间有三个空格，但实际输出是两个骰子在一条线上的非常混乱、扭曲的版本。

标签： python

解决方案

您必须将骰子保留为行列表

die3 = [
    "+-------+",
    "| *     |",
    "|   *   |",
    "|     * |",
    "+-------+",
]    


die4 = [
    "+-------+",
    "| *   * |",
    "|       |",
    "| *   * |",
    "+-------+",
]

然后你可以使用zip()来创建对[first row of die3, first row of die4]，[second row of die3, second row of die4]等等。然后你可以连接对使用"".join()并显示它

for rows in zip(die3, die4):
    #print(rows)
    print(''.join(rows))

+-------++-------+
| *     || *   * |
|   *   ||       |
|     * || *   * |
+-------++-------+

你可以用更多的骰子做同样的事情

for rows in zip(die3, die4, die4, die3):
    print(''.join(rows))

+-------++-------++-------++-------+
| *     || *   * || *   * || *     |
|   *   ||       ||       ||   *   |
|     * || *   * || *   * ||     * |
+-------++-------++-------++-------+

如果您需要骰子之间的空间，请使用空间" ".join(rows)

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