时间戳

首页 > 解决方案 > SQL Server 2014 - 按日/夜时间、周/周末、常规/加班时间汇总工作时间组

sql-server - SQL Server 2014 - 按日/夜时间、周/周末、常规/加班时间汇总工作时间组

问题描述

我有一个任务列表，
每个任务都有一个 TaskID、startTime 和 StopTime，从 1970 年 1 月 1 日开始以毫秒为单位，还有一个用户列表 (#Tasks)。

我需要计算每个用户在任务上花费的时间，按日/夜时间、周或周末、常规/加班时间划分，考虑从晚上 10:00 到上午 06:00 的夜间时间。

当然有更好的解决方案，但到目前为止我得到了这个：

IF OBJECT_ID('tempdb..#Tasks') IS NULL
    BEGIN
        create table #Tasks
        (
            TaskID nvarchar(50), 
            DateStart bigint, 
            DateStop bigint,
            Staff nvarchar(100)
        )

        insert into #Tasks values
        ('C001',1554181200000,1554190200000,'john,jack'),
        ('C002',1554202800000,1554212700000,'tom,john'),
        ('C003',1554228000000,1554246900000,'john,franck'),
        ('C004',1554613200000,1554626700000,'john')
    END
GO

declare
  @UserName     nvarchar(50)='john',
  @DateFrom     datetime='2019-04-01', 
  @DateTo       datetime='2019-04-30',
  @nStart       time='06:00:00',
  @nStop        time='22:00:00'

  select
    startday as [Day],
    sum([WeekDay]) as [WeekDay],
    sum([WeekNight]) as [WeekNight],
    sum([WeekendDay]) as [WeekendDay],
    sum([WeekendNight]) as [WeekendNight],
    sum([TotalMinutes]) as [TotalMinutes],
    0 WeekDayOverTime, 
    0 WeekNightOvertime, 
    0 WeekendDayOvertime, 
    0 WeekendNightOvertime,
    [UserName]
    ,timeframe
  from
  (
      select
        iif(isWeekend=1,NightMinutes,0) WeekendNight,
        iif(isWeekend=0,NightMinutes,0) WeekNight,
        iif(isWeekend=1,DayMinutes,0) WeekendDay,
        iif(isWeekend=0,DayMinutes,0) [WeekDay],
        TotalMinutes,
        username,
        startday,
        timeframe
       from 
       (
          select
            iif(Before6>0,Before6,0)+ iif(After22>0,After22,0) NightMinutes,
            TotalMinutes-iif(Before6>0,Before6,0)- iif(After22>0,After22,0) DayMinutes,
            TotalMinutes,
            startday,
            isWeekend,
            UserName,
            timeframe
            from 
            (
                Select 
                    (t.datestop-t.datestart)/60000 TotalMinutes,
                    datediff(n,convert(time,DATEADD(SECOND,t.DateStart/1000,'1970-01-01')),@nStart) Before6,
                    datediff(n,@nStop,convert(time,DATEADD(SECOND,t.DateStop/1000,'1970-01-01')))   After22,
                    iif((((DATEPART(DW, convert(datetime,DATEADD(SECOND,t.DateStart/1000,'1970-01-01'))) - 1 ) + @@DATEFIRST ) % 7) IN (0,6),1,0) isWeekend,
                    convert(varchar(10),DATEADD(SECOND,t.DateStart/1000,'1970-01-01'),126) startday,
                    STUFF(( SELECT distinct ' ' + convert(varchar(5),DATEADD(SECOND,t.DateStart/1000,'1970-01-01'),108)+'-'+convert(varchar(5),DATEADD(SECOND,t.DateStop/1000,'1970-01-01'),108) AS [text()]
                        FROM #Tasks tt
                        --WHERE tt.taskID=t.TaskID               
                        FOR XML PATH('') ), 1, 1, '' ) AS [timeframe],
                    @UserName UserName
                FROM #Tasks t
                WHERE t.Staff like '%'+@UserName+'%'
                and DATEADD(SECOND,t.DateStart/1000,'1970-01-01') between @DateFrom and @DateTo
            ) z
        ) zz
    ) zzz
    group by startday,username,timeframe
    order by startday

我现在需要：
1) 按天对结果进行分组，总结 WeekDay、WeekNight、WeekendDay、WeekendNight 和 TotalMinutes，并连接时间范围，例如在 4 月 2 日“05:00-07:30|11:00-13: 45|18:00-23:00"
2) 12:00 到 12:30（如果适用）之间的时间不计算，因为这是午餐时间
3) 考虑到每天 8 小时后必须计算为加班，我必须在时间和加班之间分配总分钟数，但取决于加班时间是白天还是晚上还是周末
4) 最终使用假期表

换句话说，我们应该有这个：

    Day         TotalMinutes    WeekDay WeekNight   WeekendDay  WeekendNight    WeekDayOverTime WeekNightOvertime   WeekendDayOvertime  WeekendNightOvertime    UserName    timeframe
    02/04/2019  630               420     60            0            0                 45                75                   0                    0              john      05:00-07:30|11:00-13:45|18:00-23:00
    07/04/2019  225                0       0          165           60                  0                 0                   0                    0              john      05:00-08:45

因为（4 月 2 日）我们有：
第一个任务：
60 分钟的常规夜间时间
90 分钟的常规白天时间

第二个任务：
正常白天的 165 分钟，但由于午餐时间只能数 135

第三个任务：
240 DayTime
75 NightTime
但是由于任务 1 和 2 加起来是 285 分钟，因此只有第三个任务的前 185 分钟是常规白天：剩下的 45 分钟是加班时间，而后面的 75 分钟的夜间实际上是加班时间

标签： sql-serversql-server-2014

解决方案

在这种方法中，第一个 CTE (properDates) 获取开始和停止日期时间，然后您不需要在查询中重复该公式。

第二个 CTE(splittedMinutes) 是获取与当前方法相同的数据，但第一个 CROSS APPLY 除外，它是拆分与午餐时间交叉的时间范围。第二个 CROSS APPLY 获取分钟数和 isWeekend 值。

在第三个 CTE(qualifiedMinutes) 中，我使用窗口分区来获取累积的分钟数并在应用时生成加班。

最后，我使用选择性 SUM 来区分聚合中的工作日和周末

;with properDates AS (
    SELECT TaskID, DATEADD(SECOND,t.DateStart/1000,'1970-01-01') as DateStart,DATEADD(SECOND,t.DateStop/1000,'1970-01-01') as DateStop, Staff
    FROM #Tasks t
    WHERE Staff LIKE '%' + @UserName + '%'
), splittedMinutes AS (
select
    CAST(p.DateStart AS DATE) as [Day],
    TotalMinutes,
    SUM(TotalMinutes) OVER (PARTITION BY CAST(p.DateStart AS DATE) ORDER BY b.start) AS cumulate,
    TotalMinutes - EarlyMinutes - LateMinutes  as DayTime,
    EarlyMinutes + LateMinutes as NightTime,
    isWeekend,
    CONVERT(VARCHAR(5),b.Start,108) + '-' + CONVERT(VARCHAR(5),b.Stop,108) as [timeframe]
    from properdates p
    cross apply (
        select CAST(p.DateStart As TIME) AS Start, @bStart as Stop WHERE CAST(p.DateStart AS TIME) < @bStart and CAST(p.DateStop AS TIME) > @bStart
        union 
        select @bStop as Start, CAST(DateStop AS TIME) AS Stop WHERE CAST(p.DateStop AS TIME) > @bStop and CAST(p.DateStart AS TIME) < @bStop
        union 
        select CAST(p.DateStart AS TIME) AS Start, CAST(p.DateStop AS TIME) AS Stop WHERE NOT (CAST(p.DateStart AS TIME) < @bStart and CAST(p.DateStop AS TIME) > @bStart) AND NOT (CAST(p.DateStop AS TIME) > @bStop and CAST(p.DateStart AS TIME) < @bStop)
    ) b
    cross apply (
        select 
        DATEDIFF(Minute, b.Start, b.Stop) as TotalMinutes,
        (DATEDIFF(Minute, CAST(b.Start AS TIME), @nStart) + ABS(DATEDIFF(Minute, CAST(b.Start AS TIME), @nStart))) / 2 as EarlyMinutes,
        (DATEDIFF(Minute, @nStop, CAST(b.Stop AS TIME)) + ABS(DATEDIFF(Minute, @nStop, CAST(b.Stop AS TIME)))) / 2 as LateMinutes,
        CASE WHEN DATEPART(DW, p.DateStart) IN (1,7) THEN 1 ELSE 0 END AS isWeekend 
    ) c
), qualifiedMinutes As (
    SELECT Day, TotalMinutes, RegularDay, RegularNight, OvertimeDay, OvertimeNight, isWeekend, timeframe
    FROM splittedMinutes
    OUTER APPLY (
        SELECT RegularDay = CASE WHEN cumulate <= @maxTime THEN DayTime WHEN DayTime - (cumulate - TotalMinutes - @maxTime) > 0 THEN ABS(cumulate - TotalMinutes - @maxTime) ELSE 0 END
    ) RD
    OUTER APPLY (
        SELECT OvertimeDay = DayTime - RegularDay
    ) OWD
    OUTER APPLY (
        SELECT RegularNight = CASE WHEN cumulate <= @maxTime THEN NightTime WHEN (cumulate - TotalMinutes - @maxTime + RegularDay) < 0 THEN NightTime + (cumulate - TotalMinutes - @maxTime + RegularDay) ELSE 0 END
    ) RWN
    OUTER APPLY (
        SELECT OvertimeNight = NightTime - RegularNight
    ) OWN
)

SELECT 
    Day,
    @UserName and UserName, 
    SUM(TotalMinutes) AS TotalMinutes,
    SUM(CASE WHEN isWeekend = 0 THEN RegularDay ELSE 0 END) AS WeekDay,
    SUM(CASE WHEN isWeekend = 0 THEN RegularNight ELSE 0 END) AS WeekNight,
    SUM(CASE WHEN isWeekend = 1 THEN RegularDay ELSE 0 END) AS WeekendDay,
    SUM(CASE WHEN isWeekend = 1 THEN RegularNight ELSE 0 END) AS WeekendNight,
    SUM(CASE WHEN isWeekend = 0 THEN OvertimeDay ELSE 0 END) AS WeekDayOverTime,
    SUM(CASE WHEN isWeekend = 0 THEN OvertimeNight ELSE 0 END) AS WeekNightOvertime,
    SUM(CASE WHEN isWeekend = 1 THEN OvertimeDay ELSE 0 END) AS WeekendDayOverTime,
    SUM(CASE WHEN isWeekend = 1 THEN OvertimeNight ELSE 0 END) AS WeekendNightOvertime,
    STUFF((SELECT '|' + timeframe FROM qualifiedMinutes tt WHERE tt.Day = q.Day ORDER BY timeframe FOR XML PATH('') ), 1, 1, '' ) AS [timeframe]
FROM qualifiedMinutes q
GROUP BY Day

推荐阅读