首页 > 解决方案 > 我似乎无法找到一种方法来检查我的 mysql db (php7) 中是否收到了一封电子邮件

问题描述

我创建了一个 php7 和 mySQL 网站,让用户登录并注册到一个网站。

我已确保用户不能使用与已注册的其他人相同的用户名,但我似乎无法对电子邮件执行相同的操作。

我创建了我的网站,所以当按下注册按钮时,浏览器会指向一个名为 signup.inc.php 的文件。我不知道要更改什么或如何解决它,我一直在寻找解决方案,但我很困惑这个问题,所以帮助会很好:)

我关注的部分是:

if ($resultCheck > 0) {
          header("Location: ../signup.php?error=emailtaken");
          exit();

这还包括工作用户检查器:

  else {
    $sql = "SELECT uidUsers AND emailUsers FROM users WHERE uidUsers=? AND emailUsers=?";
    $stmt = mysqli_stmt_init($conn);
    if (!mysqli_stmt_prepare($stmt, $sql)) {
      header("Location: ../signup.php?error=sqlerror");
      exit();
    }
    else{
      mysqli_stmt_bind_param($stmt, "ss", $username, $email);
      mysqli_stmt_execute($stmt);
      mysqli_stmt_store_result($stmt);
      $resultCheck = mysqli_stmt_num_rows($stmt);
      if ($resultCheck > 0) {
        header("Location: ../signup.php?error=usertaken");
        exit();
      }
      else{
        mysqli_stmt_bind_param($stmt, "s", $email);
        mysqli_stmt_execute($stmt);
        mysqli_stmt_store_result($stmt);
        $resultCheck = mysqli_stmt_num_rows($stmt);
        if ($resultCheck > 0) {
          header("Location: ../signup.php?error=emailtaken");
          exit();
        }

我尝试了一些方法来让它工作,这可能是它混乱的原因,但我似乎无法让数据库中的电子邮件检查工作。它在我的网站上显示“注册成功”,但它应该说的是“已发送电子邮件”。有什么帮助吗?这是完整的页面供参考:

<?php
if (isset($_POST['signup-submit'])){
  require 'dbh.inc.php';

  $username = $_POST['uid'];
  $email = $_POST['mail'];
  $password = $_POST['pwd'];
  $passwordRepeat = $_POST['pwd-repeat'];

  if (empty($username) || empty($email) || empty($password) || empty($passwordRepeat)) {
    header("Location: ../signup.php?error=emptyfields&uid=".$username."&mail=".$email);
    exit();
  }
  else if (!filter_var($email, FILTER_VALIDATE_EMAIL) && !preg_match("/^[a-zA-Z0-9]*$/", $username)) {
    header("Location: ../signup.php?error=invalidmailuid");
    exit();
  }
  else if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
    header("Location: ../signup.php?error=invalidmail&uid=".$username);
    exit();
  }
  else if (!preg_match("/^[a-zA-Z0-9]*$/", $username)) {
    header("Location: ../signup.php?error=invaliduid&mail=".$email);
    exit();
  }
  else if($password !== $passwordRepeat){
    header("Location: ../signup.php?error=passwordcheck&uid=".$username."&mail=".$email);
    exit();
  }
  else {
    $sql = "SELECT uidUsers AND emailUsers FROM users WHERE uidUsers=? AND emailUsers=?";
    $stmt = mysqli_stmt_init($conn);
    if (!mysqli_stmt_prepare($stmt, $sql)) {
      header("Location: ../signup.php?error=sqlerror");
      exit();
    }
    else{
      mysqli_stmt_bind_param($stmt, "ss", $username, $email);
      mysqli_stmt_execute($stmt);
      mysqli_stmt_store_result($stmt);
      $resultCheck = mysqli_stmt_num_rows($stmt);
      if ($resultCheck > 0) {
        header("Location: ../signup.php?error=usertaken");
        exit();
      }
      else{
        mysqli_stmt_bind_param($stmt, "s", $email);
        mysqli_stmt_execute($stmt);
        mysqli_stmt_store_result($stmt);
        $resultCheck = mysqli_stmt_num_rows($stmt);
        if ($resultCheck > 0) {
          header("Location: ../signup.php?error=emailtaken");
          exit();
        }
        else {
        //other
          $sql = "INSERT INTO users (uidUsers, emailUsers, pwdUsers) VALUES (?, ?, ?) ";
          $stmt = mysqli_stmt_init($conn);
          if (!mysqli_stmt_prepare($stmt, $sql)) {
            header("Location: ../signup.php?error=sqlerror");
            exit();
          }
          else {
            $hashedPwd = password_hash($password, PASSWORD_DEFAULT);

            mysqli_stmt_bind_param($stmt, "sss", $username, $email, $hashedPwd);
            mysqli_stmt_execute($stmt);
            header("Location: ../index.php?signup=success");
            exit();
          }
        }
      }
    }
  }
  msqli_stmt_close($stmt);
  msqli_close($conn);
}
else {
  header("Location: ../signup.php");
  exit();
}

我尝试修复错误,寻找解决方案,并尝试与用户名相同但 idk

我希望电子邮件不再重复,但在我的网站上,它显示“登录成功”,这是错误的。

标签: mysqlsql

解决方案


这是由于 SQL where 子句中的“AND”条件而发生的。仅验证用户名列以检查是否存在。在您的实施中,它正在检查电子邮件和用户名的组合是否存在重复项。如果要验证任一列,请在 where 子句中使用“OR”。


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