首页 > 解决方案 > 使用 count($array) 仅检索匹配的 $key

问题描述

我正在运行一个循环,$array其中我只包含具有匹配用户角色(来自 Wordpress 用户)的结果。

我有循环:

// custom function that returns the user's role (administrator, reader, etc)
$userRole = get_current_user_role();

foreach( $location_array as $key => $location ) {
    if( in_array( $userRole, $location['c'] ) ) {
        // do the things

        echo '<div style="width: calc( 100vw / ' . count($array) . ');">';
            echo $location['a'];
        echo '</div>';

    }
}

$array组成:

Array (
    [1] => Array (
        [a] => Location 1
        [b] => loc04
        [c] => Array ( [administrator] => administrator )
    )
    [2] => Array (
        [a] => Location 2
        [b] => loc23
        [c] => Array ( [administrator] => administrator, [publisher] => publisher )
    )

    [3] => Array (
        [a] => Location 3
        [b] => loc12
        [c] => Array ( [publisher] => publisher, [viewer] => viewer )
    )
) 

但是,当我尝试获取 的计数时$array,它会返回所有 的数量$key,我不知道如何将其缩小到仅来自in_array( $userRole, $location['c']

我尝试将in_array( $userRole, $location['c']from 循环放入一个变量中,然后输出它,但除了返回值 1 之外,我没有任何成功,但管理员有两个匹配项

标签: phparrayswordpressfunctionloops

解决方案


您不能在正在进行的阵列上使用计数。你需要先过滤它

您可以将数组过滤器用作:

$arr = [["b" => "loc04", "c" => ["administrator" => "administrator"]]];
$arr[] = ["b" => "loc23", "c" => ["administrator" => "administrator", "publisher" => "publisher"]];
$arr[] = ["b" => "loc12", "c" => ["publisher" => "publisher", "viewer" => "viewer"]];
$role = "administrator";
$a = array_filter($arr, function ($e) use ($role) {return in_array($role, $e["c"]);});

现在$a将包含 2 元素。

如果键与您最好使用的值相同isset(更快 - O(1) 而不是 O(n)):

$a = array_filter($arr, function ($e) use ($role) {return isset($e["c"][$role]);});

然后你可以循环$a并做:

foreach($a as $location) {
    echo '<div style="width: calc( 100vw / ' . count($a) . ');">';
    echo $location['a'];
    echo '</div>';
}

现场示例:3v4l


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