node.js - 在选项卡处于非活动状态时保持 Socket.io 活动

Question

我正在尝试实现一个代码，该代码显示站点中的在线用户列表及其上次活动时间。But a issue I'm facing is that, when the tab is inactive or the user isn't performing any action on the tab, the socket gets disconnected automatically. 如果选项卡处于打开状态，无论是否处于活动状态，我如何保持套接字处于活动状态。

应用程序.js

...
io.on('connection', function(socket){

  let userName

  socket.on('user viewing', function(user){
    let inActiveUsers = false

    for(var x = 0; x < activeUsers.length; x++) {
        if(activeUsers[x].username == user) {
            inActiveUsers = true
            activeUsers[x].last_activity = MDate.getDateTime()
            break
        }
    }

    if(!inActiveUsers) {
        activeUsers.push({"username": user, "last_activity": MDate.getDateTime()})
    }

    userName = user

    io.emit('active users', activeUsers)

  })

  socket.on('disconnect', function(){

    let userIndex = -1

    for(var x = 0; x < activeUsers.length; x++) {
        if(activeUsers[x].username == userName) {
            userIndex = x
            break
        }
    }

    if(userIndex != -1) {
      activeUsers[x].last_activity = 'NULL'
    }

    io.emit('active users', activeUsers)
  })

})
...

客户端代码

<script src="/socket.io/socket.io.js"></script>
<script>
  var socket = io();
  socket.emit('user viewing', '<%= user.username %>');
</script>

标签： node.jsexpresssocket.io