首页 > 解决方案 > 在 Tkinter 中按下给定按钮时,我无法触发随机功能

问题描述

我正在制作一个按钮,它将在 Python 的 tkinter 模块中显示一条消息。

起初,按钮上有文字。单击它时,它将显示一个消息框。消息框是“弹出”或“错误消息”。

下面的代码将显示一个执行上述语句的示例函数。

def joke1():
    messagebox.showinfo(title = "There are three types of people in this world", message = "Those who can count and those who can't.")

root = Tk()
root.title("Joke Board 1.0 by Jamlandia")
root.iconbitmap(r"C:\Users\VMWZh\Downloads\Icons8-Ios7-Messaging-Lol.ico")
button = Button(text = "There are three types of people in this world", bg = '#42f474', fg = 'black', command = joke1)
test = Button()

button.grid(column = 0, row = 0)

test.grid(column = 1, row = 0)
root.mainloop()

我想不出一种方法来编写它,以便当您按下按钮时,它将运行与按钮上显示的笑话相关的函数,然后随机绑定到一个新函数和文本以更改为与该功能相关的笑话。

标签: pythontkinter

解决方案


问题:按下按钮,...随机...变成笑话

tkinter — Tcl/Tk 的 Python 接口

Python 教程和 Python 模块


点击时随机 显示,没有.JokeButtonmessagbox

import tkinter as tk
import random

class App(tk.Tk):
    def __init__(self):
        super().__init__()

        self.joke_index = 0
        self.jokes = [("There are three types of people in this world", "Those who can count and those who can't."),
                      ('Grew up with six brothers', 'That’s how I learned to dance–waiting for the bathroom'),
                      ('Always borrow money from a pessimist.', 'He won’t expect it back.')
                      ]
       
        self.label1 = tk.Label(self)
        self.label1.grid(row=0, column=0, pady=3)
        
        self.label2 = tk.Label(self)
        self.label2.grid(row=1, column=0, pady=3)

        button = tk.Button(self,
                           text='Show next Joke',
                           command=self.show_random_joke,
                           bg='#42f474', fg='black'
                           )
        button.grid(row=2, column=0, pady=3)

    def show_random_joke(self):
        v = -1
        while v == self.joke_index:
            v = random.randrange(0, len(self.jokes)-1)
        self.joke_index = v

        self.label1['text'], self.label2['text'] = self.jokes[self.joke_index]

if __name__ == "__main__":
    App().mainloop()

用 Python 测试:3.5


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