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python - Python Bokeh 在 legend.click_policy = 'hide' 或 'mute' 中定义预选的散景

问题描述

在这个例子中 

import pandas as pd

from bokeh.palettes import Spectral4
from bokeh.plotting import figure, output_file, show
from bokeh.sampledata.stocks import AAPL, IBM, MSFT, GOOG

p = figure(plot_width=800, plot_height=250, x_axis_type="datetime")
p.title.text = 'Click on legend entries to hide the corresponding lines'

for data, name, color in zip([AAPL, IBM, MSFT, GOOG], ["AAPL", "IBM", "MSFT", "GOOG"], Spectral4):
    df = pd.DataFrame(data)
    df['date'] = pd.to_datetime(df['date'])
    p.line(df['date'], df['close'], line_width=2, color=color, alpha=0.8, legend=name)

p.legend.location = "top_left"
p.legend.click_policy="hide"

output_file("interactive_legend.html", title="interactive_legend.py example")

show(p)

默认情况下显示所有行。有没有办法在创建图表时隐藏除“IBM”之外的所有行？解决“隐藏”或“未隐藏”状态的标志是什么？

标签： pythonbokeh

解决方案

您可以使用renderer.visible = False隐藏一些字形

import pandas as pd
from bokeh.palettes import Spectral4
from bokeh.plotting import figure, show
from bokeh.sampledata.stocks import AAPL, IBM, MSFT, GOOG

p = figure(plot_width = 800, plot_height = 250, x_axis_type = "datetime", title = 'Glyphs hidden by default')

lines = {}
for data, name, color in zip([AAPL, IBM, MSFT, GOOG], ["AAPL", "IBM", "MSFT", "GOOG"], Spectral4):
    df = pd.DataFrame(data)
    df['date'] = pd.to_datetime(df['date'])
    lines[name] = p.line(df['date'], df['close'], line_width = 2, color = color, alpha = 0.8, legend = name)
    lines[name].visible = True if name == "IBM" else False

p.legend.location = "top_left"
p.legend.click_policy = "hide"

show(p)

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