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java - 错误 java.lang.NumberFormatException：对于输入字符串，程序崩溃

问题描述

我已经实现了一个应用程序，它从用户那里获取读数并返回一条消息，但是在尝试打开活动时会发生以下错误：

2019-04-21 10:03:27.179 4338-4338/com.example.mymedicare E/AndroidRuntime: FATAL EXCEPTION: main
    Process: com.example.mymedicare, PID: 4338
    java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.mymedicare/com.example.mymedicare.enteringReadings}: java.lang.NumberFormatException: For input string: ""
        at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2817)
        at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2892)
        at android.app.ActivityThread.-wrap11(Unknown Source:0)
        at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1593)
        at android.os.Handler.dispatchMessage(Handler.java:105)
        at android.os.Looper.loop(Looper.java:164)
        at android.app.ActivityThread.main(ActivityThread.java:6541)
        at java.lang.reflect.Method.invoke(Native Method)
        at com.android.internal.os.Zygote$MethodAndArgsCaller.run(Zygote.java:240)
        at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:767)
     Caused by: java.lang.NumberFormatException: For input string: ""
        at java.lang.Integer.parseInt(Integer.java:620)
        at java.lang.Integer.parseInt(Integer.java:643)
        at com.example.mymedicare.enteringReadings.onCreate(enteringReadings.java:28)
        at android.app.Activity.performCreate(Activity.java:6975)
        at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1213)
        at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2770

public class enteringReadings extends AppCompatActivity {

private MyDBHelper db;
//declares values
private Button Enter;
private EditText Temprature;
private EditText lowerBlood;
private EditText higherBlood;
private EditText heartBeat;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_entering_readings);

    //Reads values as integers
    Temprature = findViewById(R.id.Temprature);
    int temprature =Integer.parseInt( Temprature.getText().toString());
    lowerBlood = findViewById(R.id.lowerBlood);
    int Lowerblood =Integer.parseInt( lowerBlood.getText().toString());
    higherBlood = findViewById(R.id.higherBlood);
    int Higherblood =Integer.parseInt( higherBlood.getText().toString());
    heartBeat = findViewById(R.id.heartBeat);
    int Heartbeat =Integer.parseInt( heartBeat.getText().toString());

    Button Enter = findViewById(R.id.Enter);
    db = new MyDBHelper(this);

    Enter.setOnClickListener((View.OnClickListener) this);

    if (temprature <= 37 && Lowerblood <=80 && Higherblood <=120 && Heartbeat <= 72 );
    Toast.makeText(getApplicationContext(),"Your readings are fine no action required",Toast.LENGTH_LONG);
}
}

我希望应用程序允许用户输入他们的读数，我还没有实现其他两种情况，但在尝试运行应用程序后注意到了这个错误。

标签： javaandroid

解决方案

Temprature.getText()返回空字符串。空字符串不能转换为Integer. 将try-catch块添加到您的代码中以处理NumberFormatException.

int temprature = 0;
try {
    temprature = Integer.parseInt(Temprature.getText().toString());
} catch (NumberFormatException e) {
   // Log error, change value of temperature, or do nothing
}

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