python - 如何在python字典中拆分值？

Question

我有以列表形式存储的 dict 值。这是它的样子：

d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
]

在这里，在 keyLength中，我有两个值。first=steven,initial=s 我想拆分这些值并创建两个新字段并将其以更新的形式存储在字典中。

所需输出：

d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p','first':'prince','initial':'p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s','first':'steven','initial':'s'}
]

这是我尝试过的程序：

d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
]
field_to_split = "Length"
split_using1 = ','
split_using2 = '='
b =[]
for i in d:
    s = i[field_to_split].split(split_using1)
    print(s)
    b.append(s)
    #print(s)
print(b)

我怎样才能使这成为可能...

标签： pythonpython-3.xlistdictionaryfor-loop

Answer 1

使用简单的迭代。

前任：

d = [
    {'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
    {'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
    ]

for i in d:
    for j in i['Length'].split(","):    #Split string by comma
        i.update(dict([j.split("=")]))  #Split string by eq sign and use dict() method to create a dictionary 

输出：

[{'Classification': 'Automatic,Transmission',
  'Driveline': 'Rear-wheel drive',
  'Fuel_Type': 'Gasoline',
  'Hybrid': 'False',
  'Length': 'first=prince,initial=p',
  'Number_of_Forward_Gears': 6,
  'first': 'prince',
  'initial': 'p'},
 {'Classification': 'Automatic,Transmission',
  'Driveline': 'Rear-wheel drive',
  'Fuel_Type': 'Gasoline',
  'Hybrid': 'False',
  'Length': 'first=steven,initial=s',
  'Number_of_Forward_Gears': 6,
  'first': 'steven',
  'initial': 's'}]