mysql - 从 SQL 中的四个相关表中获取最小值
问题描述
我有几个问题,
首先,当我阅读一些文章时,我知道我将在这个问题中使用内部联接来实现 SQL 代码。我有以下表格:
医院表:
id | hospital_name | adress | city_id
-------------------------------------------
1 | pars | 55,6LA| 2
2 | ghaem | 12.9GI| 2
3 | Mehr | 632.Sp| 2
4 | Erfan | 21,6UJ| 3
5 | Razavi | 31.jjI| 3
6 | Mohab | 65.Spi| 1
城市表:
id | cityname
--------------------
1 | LosAngels
2 | NewYork
3 | Colifornia
治疗表:
id | TreatmentName
----------------------
1 | nose surgery
2 | Orthopedic
3 | Knee joint replacement
治疗价格表:
id | Treatments_id | Hospital_id | Price
------------------------------------------
1 | 1 | 1 | 700
2 | 1 | 6 | 800
3 | 1 | 4 | 900
4 | 2 | 1 | 500
5 | 2 | 2 | 700
6 | 2 | 3 | 300
7 | 3 | 1 | 600
7 | 3 | 2 | 450
我的问题是如何按城市代码找到每家医院的最低治疗价格。
如果城市 ID为2,我需要如下表视图:
price | hospital_name | treatment_name|
-------------------------------------------
700 | pars | nose surgery
300 | Mehr | Orthopedic
450 | ghaem | Knee joint replacement
这是我的SQL代码:
SELECT Min(treatment_prices.dollar) AS price,
hospitals.name_en AS hname,
treatments.title_en AS title
FROM treatment_prices
INNER JOIN hospitals
ON hospitals.id = treatment_prices.hospital_id
INNER JOIN treatments
ON treatments.id = treatment_prices.treatment_id
WHERE hospitals.city_id = 2
GROUP BY treatment_prices.treatment_id
任何帮助将不胜感激。*
解决方案
您正在寻找城市中哪家医院的哪种手术最便宜。
在 MySQL 5.x 中,您必须使用一些内部子查询来查找医院最便宜的程序,然后再次将其连接回您的表以获取您需要的数据。
有关设置,请参阅 Fiddle。
MySQL 5.x:
首先,您想找到最便宜的手术价格,按您所需的城市和该城市的医院进行过滤。
查询 1:
SELECT tp.Treatments_ID, min(tp.Price) AS price
FROM treatment_prices tp
INNER JOIN Hospital h ON tp.Hospital_ID = h.ID
INNER JOIN Cities c ON h.city_id = c.id
AND c.ID = 2
GROUP BY tp.Treatments_ID
这给你
结果:
| Treatments_ID | price |
|---------------|-------|
| 1 | 700 |
| 2 | 300 |
| 3 | 450 |
现在,您可以将其用作子查询以再次链接回主表以检索您要查找的数据。
查询 2:
SELECT t2.TreatmentName, h2.Hospital_Name, s1.Price
FROM (
SELECT tp.Treatments_ID, min(tp.Price) AS price
FROM treatment_prices tp
INNER JOIN Hospital h ON tp.Hospital_ID = h.ID
INNER JOIN Cities c ON h.city_id = c.id
AND c.ID = 2
GROUP BY tp.Treatments_ID
) s1
INNER JOIN treatment_prices tp2 ON s1.Treatments_ID = tp2.Treatments_ID
AND s1.price = tp2.Price
INNER JOIN Hospital h2 ON tp2.Hospital_ID = h2.ID
INNER JOIN Treatments t2 ON tp2.Treatments_ID = t2.ID
结果:
| TreatmentName | Hospital_Name | Price |
|------------------------|---------------|-------|
| nose surgery | pars | 700 |
| Orthopedic | Mehr | 300 |
| Knee joint replacement | ghaem | 450 |
在更高版本的 MySQL 或任何其他允许窗口函数的 SQL 语言中,这要容易得多。
MySQL 8+:
SELECT s1.TreatmentName, s1.Hospital_Name, s1.Price
FROM (
SELECT t.TreatmentName, h.Hospital_Name, tp.Price
, ROW_NUMBER() OVER (PARTITION BY tp.Treatments_ID ORDER BY tp.Price) AS rn
FROM treatment_prices tp
INNER JOIN Hospital h ON tp.Hospital_ID = h.ID
INNER JOIN Cities c ON h.city_id = c.id
AND c.ID = 2
INNER JOIN Treatments t ON tp.Treatments_ID = t.ID
) s1
WHERE rn = 1
;
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=9b28f7543c3b127990654ad9e401c11a
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