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python - 我想在turtlegraphics的墙上有一个弹跳球，但他们停下来，他们徘徊并发送错误

问题描述

我画了一些三角形，它们应该在墙上弹跳，但它们不弹跳，它们不直走，几秒钟后它们会打印一条错误消息。

当我让三角形仅以十字形移动时，三角形动摇并出现错误消息。

import turtle
import random
def draw_sq(t,distance=400):#Draw a box
    t.penup()
    t.goto(-200,200)
    t.pendown()
    t.forward(distance)
    t.right(90)
    t.forward(distance)
    t.right(90)
    t.forward(distance)
    t.right(90)
    t.forward(distance)
    t.penup()
    t.goto(0,0)
    t.pendown()
def add_tri():
    global l_tri
    t=turtle.Turtle()
    t.shape("triangle")
    x=-200
    y=random.randint(-200,200)
    t.penup()
    t.goto(x,y)
    t.setheading(random.randint(-89,89))
    # make triangle and start
    l_tri.append(t)# add a triangle to list
def successMan():#write word succes 
    global playing
    if playing==True:
        t.write("success")

def turn_right():
    global right
    right = True

def turn_left():
    global left
    left = True

def turn_up():
    global up
    up = True

def turn_down():
    global down
    down = True

def _turn_right():
    global right
    right = False

def _turn_left():
    global left
    left = False

def _turn_up():
    global up
    up = False

def _turn_down():
    global down
    down = False

def is_touch(x,y,triangle,threshold=20):
    global playing
    if((x-triangle.position()[0])**2+(y-triangle.position()[1])**2<=threshold**2):
        playing=False#if triangle touches the turtle make playing False

def timer_go():
    global heading
    global l_tri
    global t
    global playing
    global up
    global left
    global down
    global right# heading is where turtle heads
    if up:
        if right:
            heading=45
        elif left:
            heading=135
        elif down:
            heading = heading
        else:
            heading=90
    if down:
        if right:
            heading=315
        elif left:
            heading=225
        elif up:
            pass
        else:
            heading = 270
    if left:
        if right:
            heading = heading
        elif up:
            pass
        elif down:
            pass
        else:
            heading = 180
    if right:
        if left:
            pass
        elif up:
            pass
        elif down:
            pass
        else:
            heading = 0

    t.setheading(heading)
    t.forward(10)
        # turtle controller
    for i in range(3):#triangles move
        if (l_tri[i].position()[0]<-200):
            l_tri[i].setheading(180-l_tri[i].heading())
            l_tri[i].forward(10)
        if (l_tri[i].position()[0]>200):
            l_tri[i].setheading(180-l_tri[i].heading())
            l_tri[i].forward(10)
        if (l_tri[i].position()[1]<-200):
            l_tri[i].setheading(-l_tri[i].heading())
            l_tri[i].forward(10)
        if (l_tri[i].position()[1]>200):
            l_tri[i].setheading(-l_tri[i].heading())
            l_tri[i].forward(10)#triangle bounces on the wall
        l_tri[i].forward(10)
        is_touch(t.position()[0],t.position()[1],l_tri[i],threshold=20)
    # check triangle and turtle
    if (playing==False):
        t.write("FAIL")
        #Fail

up = False
down = False
right = False
left = False
playing = True
heading = 0
l_tri = []

t = turtle.Turtle()
t.shape('turtle')
t.speed(0)
draw_sq(t)
screen = t.screen

screen.onkeypress(turn_right, 'Right')
screen.onkeypress(turn_left, 'Left')
screen.onkeypress(turn_up, 'Up')
screen.onkeypress(turn_down, 'Down')
screen.onkeyrelease(_turn_right, 'Right')
screen.onkeyrelease(_turn_left, 'Left')
screen.onkeyrelease(_turn_up, 'Up')
screen.onkeyrelease(_turn_down, 'Down')


for i in range(3):
    add_tri()
for i in range(1,200):
    time = i*100
    screen.ontimer(timer_go, time)
screen.ontimer(successMan,20000)
screen.listen()
screen.mainloop()

这应该是一个玩家避开盒子里的三角形的游戏。

标签： pythonturtle-graphics

解决方案

当我运行它时，我看到错误

RecursionError: maximum recursion depth exceeded while calling a Python object

但我没有看到代码中的递归。

也许问题是

for i in range(1,200):
    time = i*100
    screen.ontimer(timer_go, time)

可能它创建了太多功能。

你可以运行一次

screen.ontimer(timer_go, 100)

并在结束时再次使用它timer_go() 

def timer_go():

    # ... rest of code ...

    screen.ontimer(timer_go, 100)

它会一直重复。

你甚至可以在官方文档中看到这个方法：turtle.ontimer

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