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java - Java Streams 中的 lambda 函数集合

问题描述

我有一个流功能KStream<K, V>[] branch(final Predicate<? super K, ? super V>... predicates)。我想动态创建一个谓词列表。那可能吗？

       KStream<Long, AccountMigrationEvent>[] branches = stream
           .map((key, event) -> enrich(key, event))
           .branch(getStrategies());

        [...]

        private List<org.apache.kafka.streams.kstream.Predicate<Long, AccountMigrationEvent>> getStrategies() {
            ArrayList<Predicate<Long, AccountMigrationEvent>> predicates = new ArrayList<>();
            for (MigrationStrategy strategy : strategies) {
                predicates.add(new org.apache.kafka.streams.kstream.Predicate<Long, AccountMigrationEvent>() {
                    @Override
                    public boolean test(Long key, AccountMigrationEvent value) {
                        return strategy.match(value);
                    }
                });

            }
            return predicates;
        }

标签： javajava-8java-streamapache-kafka-streams

解决方案

我没有测试过这段代码，但理论上它应该可以工作：

//All the predicates mentioned in here are of type org.apache.kafka.streams.kstream.Predicate
private Predicate<Long, AccountMigrationEvent>>[] getStrategies() {

  List<Predicate<Long, AccountMigrationEvent>> predicates = strategies.stream()
            .map(strategy -> (Predicate<Long, AccountMigrationEvent>>) (key, value) -> strategy.matches(value))
            .collect(toList());

    // branch() method on KStream requires an array so we need to transform our list
    return predicates.toArray(new Predicate[predicates.size()]);
}

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