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首页 > 解决方案 > 如何获取用户输入并将其成功存储在 ArrayList 中？那么如何让我的程序向我展示 ArrayList 中的所有元素？

java - 如何获取用户输入并将其成功存储在 ArrayList 中？那么如何让我的程序向我展示 ArrayList 中的所有元素？

问题描述

我想要一个将员工详细信息存储在数组列表中的程序。我想提示用户输入并将每个结果存储在数组列表中。我该怎么做呢？之后如何查看存储在数组列表中的所有内容？它不需要反映我拥有的代码，只是似乎无法弄清楚我如何拥有一个带有 setter 和 getter 的类，然后创建一个新的主类提示用户输入并将该输入存储在 arraylist 中。

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class salesPersonMain {


    public static void main(String[] args) throws InputValidationException {

        Scanner input = new Scanner(System.in);
        //ask user for input and get input
        System.out.println("Enter id: ");
        int id = Integer.parseInt(input.nextLine());

        System.out.println("Enter first name:");
        String firstName = input.nextLine();

        System.out.println("Enter last name:");
        String lastName = input.nextLine();
        //save in array list
        List<salesPerson> sPerson = new ArrayList<salesPerson>();

        sPerson.add(new salesPerson(id, firstName, lastName));

    }
}

I have another class for the salesperson:

import java.util.ArrayList;

public class salesPerson<sPerson> {
    //create variables for sales person
    private int id;
    private String firstName;
    private String lastName;
 public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) throws InputValidationException {
        if (firstName.matches("\\p{Upper}(\\p{Lower}){2,20}")) {
        } else {
            throw new InputValidationException();
        }
        {
            this.firstName = firstName;
        }
    }

    public String getLastName() {
        return lastName;
    }

    public void setLastName(String lastName)throws InputValidationException {
        if (lastName.matches("\\p{Upper}(\\p{Lower}){2,20}")) {
        } else {
            throw new InputValidationException();
        }
        {
            this.lastName = lastName;
        }
    }
 //creates array of salespeople
        private ArrayList<sPerson> salesPerson;

        public salesPerson() {
            salesPerson = new ArrayList<>();
        }
        //adds new salesperson to the array
        public void add(salesPerson sPerson) {
            salesPerson.add((sPerson) sPerson);
        }

标签： javaooparraylist

解决方案

您需要一个循环来重复获取输入：

public static void main(String[] args) throws InputValidationException {

    Scanner input = new Scanner(System.in);
    List<salesPerson> sPerson = new ArrayList<salesPerson>();

    // Loop forever
    // Need a way to break the loop. One option: have the user
    // input "q" for quit
    while (true) {

        //ask user for input and get input
        System.out.println("Enter id ('q' to quit): ");
        String temp = input.nextLine();
        if (temp.equals("q")) break;

        int id = Integer.parseInt(temp);
           // This should be in try/catch in case parseInt fails

        System.out.println("Enter first name:");
        String firstName = input.nextLine();

        System.out.println("Enter last name:");
        String lastName = input.nextLine();

        //save in array list
        sPerson.add(new salesPerson(id, firstName, lastName));
    }

    // Print the list
    sPerson.forEach(System.out::println);
}

因此它可以正确打印出来，您需要覆盖类toString中的函数salesPerson：

public class salesPerson {
    // Other code here.....

    @Override
    public String toString() {
        return id + "," + firstName + " " + lastName;
    }
}

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