sql - DATE_DIFF，但只计算工作日

Question

我有一个相当简单的查询；它看起来像这样：

SELECT
order_date,
pickup_date,
DATE_DIFF(pickup_date,order_date, day) order_to_pickup
FROM
`orders.table`

唯一的问题是，我需要计算工作日的日期差异，而不是所有天。

所以不是上面的查询返回：

+------------+-------------+-----------------+
| order_date | pickup_date | order_to_pickup |
+------------+-------------+-----------------+
| 3/29/19    | 4/3/19      |               5 |
| 3/29/19    | 4/2/19      |               4 |
+------------+-------------+-----------------+

我希望它返回：

+------------+-------------+-----------------+
| order_date | pickup_date | order_to_pickup |
+------------+-------------+-----------------+
| 3/29/19    | 4/3/19      |               2 |
| 3/29/19    | 4/2/19      |               3 |
+------------+-------------+-----------------+

标签： sqlgoogle-bigquerydatediff

Answer 1

这应该是@Elliott Brossard 提到的简化的非暴力解决方案：

select
  order_date,
  pickup_date,
  case 
    when date_diff(pickup_date, order_date, week) > 0 
      then date_diff(pickup_date, order_date, day) - (date_diff(pickup_date, order_date, week) * 2)
    else
      date_diff(pickup_date, order_date, day) 
  end
from `orders.table`