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c# - Unity C#中嵌套字典的奇怪行为

问题描述

我在字典中使用字典。分配的最后一个键值也将存储为所有先前键的值，即使各个键分配不同。我错过了什么吗？

Dictionary<string, Dictionary <int,bool>> seenValsRounds= new Dictionary<string, Dictionary<int, bool>>();

void prepareRoundsVals()
    {       
        Dictionary <int,bool> roundVals = new Dictionary<int, bool> ();
        roundVals.Add (0,false);
        seenValsRounds.Add ("A", roundVals);
        seenValsRounds.Add ("B", roundVals);
        seenValsRounds.Add ("C", roundVals);
        seenValsRounds.Add ("D", roundVals);
        seenValsRounds ["A"] [0] = false;
        seenValsRounds ["B"] [0] = false;
        seenValsRounds ["C"] [0] = false;
        seenValsRounds ["D"] [0] = true;
        foreach (KeyValuePair<string, Dictionary<int,bool>> kvp in seenValsRounds) {            
            Debug.Log(kvp.Key + " in round " + 0 + ": " + seenValsRounds [kvp.Key][0]);     
        }
    }

预期结果：A 为假，B 为假，C 为假，D 为真

实际结果：A为真，B为真，C为真，D为真

根据答案和评论的建议在下面解决。每个嵌套字典也应该是“新的”：

        Dictionary <int,bool> roundVals1 = new Dictionary<int, bool> ();
        Dictionary <int,bool> roundVals2 = new Dictionary<int, bool> ();
        Dictionary <int,bool> roundVals3 = new Dictionary<int, bool> ();
        Dictionary <int,bool> roundVals4 = new Dictionary<int, bool> ();
        roundVals1.Add (0,false);
        roundVals2.Add (0,false);
        roundVals3.Add (0,false);
        roundVals4.Add (0,false);
        seenValsRounds.Add ("A", roundVals1);
        seenValsRounds.Add ("B", roundVals2);
        seenValsRounds.Add ("C", roundVals3);
        seenValsRounds.Add ("D", roundVals4);

标签： c#dictionaryunity3dnested

解决方案

那是因为您在 seenValsRounds 字典中放置了对 roundVals 字典对象的相同引用。您应该为 A、B、C 和 D 创建一个新字典。

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