java - 如何在 java 中执行这样的 Post 请求？

Question

我有一个像这样的 Curl 发布请求程序。我怎样才能在java中完成这项工作？

curl -X POST \
-H "api_key: xxxxxxxxxxxxx" \
-H "speed: 0" \
-H "voice: male" \
-H "prosody: 1" \
-H "Cache-Control: no-cache" \
-d 'This is the text to transfer' \
"http://somewhere.com"

标签： javacurl

Answer 1

我使用Apache创建一个可运行的POST请求示例

import org.apache.commons.io.IOUtils;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.ContentType;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.HttpClients;

import java.io.IOException;
import java.io.InputStream;
import java.nio.charset.StandardCharsets;
...

public static void main(String[] args) throws IOException {
    HttpClient httpclient = HttpClients.createDefault();
    HttpPost httppost = new HttpPost("https://reqres.in/api/register");

    // Simple data
    httppost.setEntity(
        new StringEntity("{\"email\":\"[e-mail]\",\"password\":\"pistol\"}",ContentType.create("application/json", StandardCharsets.UTF_8)));

    // Simple Header
    httppost.setHeader("cache-control", "no-cache");

    // Execute and get the response.
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity entity = response.getEntity();
    System.out.println("Status: " + response.getStatusLine().toString());
    if (entity != null) {
      try (InputStream instream = entity.getContent()) {
        System.out.println("response: " + IOUtils.toString(instream, StandardCharsets.UTF_8));
      }
    }
  }

来自的回应System.out.println()

状态：HTTP/1.1 200 OK

响应：{"id":4,"token":"QpwL5tke4Pnpja7X4"}