c# - Why C++ msgpack-c adds number 13 (0x0D) before number 10 (0x0A), but C# MessagePack-CSharp does not?

Question

I was trying to use MessagePack to serialize integers from 0 to 127 in C++ and in C# on Windows, but the results are not the same. msgpack-c inserts 0x0D between 0x09 and 0x0A, but MessagePack-CSharp does not. Why is that?

OS: Windows 10

IDE: Visual Studio 2019

C#

library:

https://github.com/neuecc/MessagePack-CSharp

code:

using System.Collections.Generic;
using System.IO;

class Program
{
    static void Main(string[] args)
    {
        using (FileStream fileStream = new FileStream("CSharp.msgpack", FileMode.Create, FileAccess.Write))
        {
            List<int> list = new List<int>();

            for (int i = 0; i < 128; ++i)
            {
                list.Add(i);
            }

            MessagePackSerializer.Serialize(fileStream, list);
        }
    }
}

result:

C++

library:

https://github.com/msgpack/msgpack-c

code:

#include <msgpack.hpp>
#include <vector>
#include <iostream>
#include <fstream>

int main(void)
{
    std::ofstream OutputFileStream;

    std::vector<int> list;

    for (int i = 0; i < 128; ++i)
    {
        list.push_back(i);
    }

    OutputFileStream.open("Cpp.msgpack");

    msgpack::pack(OutputFileStream, list);

    OutputFileStream.close();
}

result:

标签： c#c++msgpackbinary-serialization

Answer 1

由于您以文本模式在 c++ 中打开文件，因此如果 Windows 上不存在每个\n(ASCII 10) ，则每个 (ASCII 13) 都将在前面加上 (ASCII 13)。\r您需要以二进制模式打开文件，以免发生这种情况。

OutputFileStream.open("Cpp.msgpack", std::ofstream::binary);