javascript - 按属性对三个不同的对象数组进行排序

Question

我需要对一个Date字段进行排序的三个不同的对象数组，其中该字段在每个组中具有不同的名称。

下面是我的数据示例：

const documents = [
{
    documentId: 'ADB0125A',
    fileName: 'test_2018.pdf',
    date': '2017-12-02T19:08:52+01:00'  // Field to sort by
},
{
    documentId: '123456',
    fileName: 'test2_2018.pdf',
    date': '2017-12-12T22:08:52+01:00'  // Field to sort by
},
{
    documentId: '121212',
    fileName: 'test3_2018.pdf',
    date': '2018-05-22T23:08:52+01:00'  // Field to sort by
}];

const conversations = [
{
    conversationId: '1102',
    lastUpdate: '2015-10-10T18:19:12+01:00'  // Field to sort by
},
{
    conversationId: '5622',
    lastUpdate: '2019-08-16T18:19:12+01:00'  // Field to sort by
},
{
    conversationId: '112',
    lastUpdate: '2015-10-26T18:19:12+01:00'  // Field to sort by
}];

const invoices = [
{
    invoiceId: "20100392077",
    rechnungsDatum: "2019-02-10"  // Field to sort by
},
{
    invoiceId: "5550392077",
    rechnungsDatum: "2018-02-05"  // Field to sort by
},
{
    invoiceId: "3336392077",
    rechnungsDatum: "2018-12-11"  // Field to sort by
}];

目标：.reverse()返回最新的 4 个结果（一旦我列出了最后一组结果，我就可以得到ASC），与它们来自哪个来源无关。我希望得到：

const result = [
    {
        conversationId: '5622',
        lastUpdate: '2019-08-16T18:19:12+01:00'
    },
    {
        invoiceId: "20100392077",
        rechnungsDatum: "2019-02-10"
    },
    {
        invoiceId: "3336392077",
        rechnungsDatum: "2018-12-11"
    },
    {
        documentId: '121212',
        fileName: 'test3_2018.pdf',
        date': '2018-05-22T23:08:52+01:00'
    }
]

是否可以对所有三个对象使用独特的Array.sort方法，或者唯一的方法是将它们成对比较并从部分结果中构建结果？

标签： javascriptarraystypescript

Answer 1

您可以获取一个对象，其中包含所需日期属性的 replacemnt 键和一个保留源和标准化日期属性的平面数组，对数组进行排序并取回前四个元素。

最后删除不必要的信息并检索原始对象结构。

const
    documents = [{ documentId: 'ADB0125A', fileName: 'test_2018.pdf', date: '2017-12-02T19:08:52+01:00' }, { documentId: '123456', fileName: 'test2_2018.pdf', date: '2017-12-12T22:08:52+01:00' }, { documentId: '121212', fileName: 'test3_2018.pdf', date: '2018-05-22T23:08:52+01:00' }],
    conversations = [{ conversationId: '1102', lastUpdate: '2015-10-10T18:19:12+01:00' }, { conversationId: '5622', lastUpdate: '2019-08-16T18:19:12+01:00' }, { conversationId: '112', lastUpdate: '2015-10-26T18:19:12+01:00' }],
    invoices = [{ invoiceId: "20100392077", rechnungsDatum: "2019-02-10" }, { invoiceId: "5550392077", rechnungsDatum: "2018-02-05" }, { invoiceId: "3336392077", rechnungsDatum: "2018-12-11" }]
    keys = { documents: 'date', conversations: 'lastUpdate', invoices: 'rechnungsDatum' },
    result = Object
        .entries({ documents, conversations, invoices })
        .reduce((r, [k, v]) => [...r, ...v.map(payload => ({ payload, date: payload[keys[k]] }))], [])
        .sort((a, b) => b.date.localeCompare(a.date))
        .slice(0, 4)
        .map(({ payload }) => payload);

console.log(result);

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