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python - 对最后一个空格后的 grep 输出数值进行排序

问题描述

启动 grep 后，我得到以下输出：

2.txt:;Number of recorded Units: 16
3.txt:;Number of recorded Units: 15
4.txt:;Number of recorded Units: 26
5.txt:;Number of recorded Units: 22
6.txt:;Number of recorded Units: 12
7.txt:;Number of recorded Units: 3
8.txt:;Number of recorded Units: 19
9.txt:;Number of recorded Units: 3
10.txt:;Number of recorded Units: 7
11.txt:;Number of recorded Units: 3
12.txt:;Number of recorded Units: 35

例如，我已经安装了 gawk，但我不知道如何为此编写代码。我希望这样的输出：我有傻瓜，有人可以提供：

7.txt:;Number of recorded Units:    3
9.txt:;Number of recorded Units:    3
11.txt:;Number of recorded Units:   3
10.txt:;Number of recorded Units:   7
6.txt:;Number of recorded Units:   12
3.txt:;Number of recorded Units:   15
2.txt:;Number of recorded Units:   16
1.txt:;Number of recorded Units:   18
8.txt:;Number of recorded Units:   19
5.txt:;Number of recorded Units:   22
4.txt:;Number of recorded Units:   26
12.txt:;Number of recorded Units:  35

（条目的顺序（此处为 3）相同的值并不重要）。还是有其他更适合的工具/程序（例如 Python 脚本）？

标签： pythonawkgrep

解决方案

试试这个：

..yourGrep|sort -n -t':' -k3

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