javascript - 如何在ajax函数中打印到控制台每行代码的返回值？

Question

我想查看ajax函数中每一行代码的返回值。下面的代码给了我错误 1 ​​和 e。现在我想通过打印函数每一行的返回值来准确检查导致错误的原因。这是代码：

<script type="text/javascript">
function editTitleModalSubmit(titleId) {
    console.log("1");
    event.preventDefault();
    $.ajax({
        url: 'functions/administration-functions.php',
        type: 'POST',
        data: { "title": $('#editadminTitle').val(), "units": $('#editadminUnits').val(), "category": $('#editadminCategory').val(), "titleId": $('#adminTitleId').val(), "typeId": $('#adminTypeId').val() },
        dataType: "json",
        success: function() {
            $('#adminForm').trigger('reset');
            resultAlert('#adminResult', '#resultAdminContent', '<strong>You data was succefully saved!</strong>', 'alert-success');
        },
        error: function() {
            console.log("e");
        }
    });
}
</script>

管理-functions.php

<?php
    require_once './queries.php';
    $title   = filter_input(INPUT_POST, "title");
    $units    = filter_input(INPUT_POST, "units");
    $category = filter_input(INPUT_POST, "category");
    $typeId   = filter_input(INPUT_POST, "typeId");
    $titleId  = filter_input(INPUT_POST, "titleId");
    echo Queries::editTitle($title, $units, $category, $titleId, $typeId);
?>

标签： javascriptphpajaxerror-handling

Answer 1

您没有将失败分配给任何东西，而是e作为字符串读取。尝试用以下代码替换错误部分：

error: function(error) {
    console.log(error);
}