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python - Python删除最低值

问题描述

这是我必须翻译成 python 的伪代码

A=99
LENGTH= LENGTH(list)
LIST= 92 50 26 82 73 
for P in range 0 to LENGTH-1
    IF LIST[P] <A THEN
        A=LIST[P]
        B=P
    ENDIF
ENDFOR
IF B < LENGTH THEN
    for P in range B to LENGTH -2
        LIST[P] = LIST[P+1]
    ENDFOR
ENDIF
LENGTH=LENGTH-1
LIST[LENGTH]=NULL

我尝试在下面进行编码，该代码旨在从 LIST 中删除最小值

a = 99
list=[92,50,26,82,73]

for  p in  range  (0,len(list) - 1):
    if list[p] < a :
        a = list[p] 
        b = p 

print (list) #I just added this to see what was happening

if  b < len(list):
    for p in range (b,len(list)-2):
        list[p]=list[p]+1

list=len(list)-1

print (list)
#I just added this to see what was happening

我已经编写了上面的代码，它不会删除最低值

标签： pythonpseudocode

解决方案

你真的很接近，这里是更正：

A = 99

l = [92, 50, 26, 82, 73]

LENGTH = len(l)

for P in range(LENGTH):
    if l[P] < A:
        A=l[P]
        B=P

if B < LENGTH:
    for P in range (B, LENGTH - 1):
        l[P] = l[P+1]


LENGTH=LENGTH-1
l[LENGTH]=None

现在试试：

print(l) # [92, 50, 82, 73, None]

注意： LENGTH-1andLENGTH-2更改为LENGTHandLENGTH-1因为 Python 使用基于 0 的索引。

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