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ios - 将“获取”请求数据分配给文本字段

问题描述

我的获取数据响应就像

我希望“标题”和“日期”应该显示在我的视图控制器“标签值”中

应用程序运行时获取方法调用，数据应显示在文本字段“或”标签中

我的代码是

guard let url = URL(string: "https://jsonplaceholder.typicode.com/users") else { fatalError() }

let session = URLSession.shared
session.dataTask(with: url) { (data, response, error) in
    if let response = response {
        print(response)
    }

    if let data = data {
        print(data)
        do {
            let json = try JSONSerialization.jsonObject(with: data, options: [])
            print(json)
        } catch {
            print(error)
        }

    }
}.resume()

输出是：

[
  {
    "id": 1,
    "name": "Leanne Graham",
    "username": "Bret",
    "email": "Sincere@april.biz",
    "address": {
      "street": "Kulas Light",
      "suite": "Apt. 556",
      "city": "Gwenborough",
      "zipcode": "92998-3874",
      "geo": {
        "lat": "-37.3159",
        "lng": "81.1496"
      }
    },
    "phone": "1-770-736-8031 x56442",
    "website": "hildegard.org",
    "company": {
      "name": "Romaguera-Crona",
      "catchPhrase": "Multi-layered client-server neural-net",
      "bs": "harness real-time e-markets"
    }
  },
  {
    "id": 2,
    "name": "Ervin Howell",
    "username": "Antonette",
    "email": "Shanna@melissa.tv",
    "address": {
      "street": "Victor Plains",
      "suite": "Suite 879",
      "city": "Wisokyburgh",
      "zipcode": "90566-7771",
      "geo": {
        "lat": "-43.9509",
        "lng": "-34.4618"
      }
    },
]

我想打印“用户名”：“电子邮件”：我的故事板标签中的值

标签： iosjsonswiftdictionaryget

解决方案

结果包含多个用户，因此您应该首先遍历它们并找到您想要的用户。然后，您可以在主线程中的 UI 元素上设置文本。

guard let url = URL(string: "https://jsonplaceholder.typicode.com/users") else { fatalError() }

typealias User = [String: Any]

let session = URLSession.shared
session.dataTask(with: url) { (data, response, error) in
    if let response = response {
        print(response)
    }

    if let data = data {
        print(data)
        do {
            let usersJson = try JSONSerialization.jsonObject(with: data, options: []) as! [User]
            print(usersJson)

            // Since the result is an array of users
            for user in usersJson {
                guard let userName = user["username"] as? String else { return assertionFailure("Invalid username") }
                print(userName)

                // All UI works should done in main thread
                DispatchQueue.main.async {
                    <#usernameLabel#>.text = username
                }
            }            
        } catch {
            print(error)
        }

    }
}.resume()

我建议你看看Swift Codable。它将提高您的编码并最大限度地减少语法和人为错误。

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