laravel - 在laravel 5.7中将json数组转换为json对象

Question

我正在使用连接查询从数据库中获取数据laravel并传递给json并在数组中获取一些结果，但我想要我在下面给出的对象

控制器代码：

$resultPastActivity= DB::table('table_user_create_activity')
                            ->join('table_sub_category','table_user_create_activity.selected_activity_id', '=', 'table_sub_category.sub_category_id')
                            ->select('sub_category_name','area','activity_type','activity_date','start_time','end_time')
                            ->whereDate('activity_date', '<', $todayDate)
                            ->where('user_id',$user_id)
                            ->get();

 return response()->json(['success' => '1','data' =>$resultPastActivity]);

上面的代码将给出数组中的以下 json 实际上我想要对象中的 json

{
    "success": "1",
    "data": [
        {
            "sub_category_name": "Badminton",
            "area": "Rankala lake",
            "activity_type": "1",
            "activity_date": "2018-01-12",
            "start_time": "15:04:49",
            "end_time": "20:05:69"
        },
        {
            "sub_category_name": "Football",
            "area": "Devakar panad",
            "activity_type": "1",
            "activity_date": "2018-01-15",
            "start_time": "15:04:49",
            "end_time": "20:05:69"
        },
    ]
}



i want json as follows
{
    "success": "1",
    "data": {
        {
            "sub_category_name": "Badminton",
            "area": "Rankala lake",
            "activity_type": "1",
            "activity_date": "2018-01-12",
            "start_time": "15:04:49",
            "end_time": "20:05:69"
        },
        {
            "sub_category_name": "Football",
            "area": "Devakar panad",
            "activity_type": "1",
            "activity_date": "2018-01-15",
            "start_time": "15:04:49",
            "end_time": "20:05:69"
        },
    }
}

标签： laravel

Answer 1

您想要的不是有效的 JSON，您可以在这里查看：https ://jsonformatter.curiousconcept.com/

因此，您无法创建这样的输出，并且如果您强制它，将接收它的应用程序将无法正确解析它，因此它没有意义。