javascript - 从 json 数组中删除未定义的键

Question

我有以下 JS 数组。删除所有未定义键的行的最佳方法是什么？

json=[{email: "[e-mail]", first: "Joao", last: "Bastos", gender: "Male", phone: "3.51939e+11"},
      {email: "", first: undefined, last: undefined, gender: undefined, phone: undefined}, 
      (...)];

我尝试了以下代码，但无法正常工作。我究竟做错了什么？

cleanEmptyRows(json){

var i=0;
var row_to_remove=[];

json.forEach(function(element) {
    for (var key in element) {
        if(element[key]==null){
        row_to_remove.push(i);
        break;
        }
    }
    i++;
});


row_to_remove.forEach(function(element){
    var index = json.indexOf(element);
    if (index > -1) {
        json.splice(index, 1);
    }
});

标签： javascriptjavascript-objects

Answer 1

简单的解决方案JSON.parse(JSON.stringify(x))，

var t = [{email: "[e-mail]", first: "Joao", last: "Bastos", gender: "Male", phone: "3.51939e+11"},
      {email: "", first: undefined, last: undefined, gender: undefined, phone: undefined}];

     
console.log(JSON.parse(JSON.stringify(t)));

如果要删除整行，可以按照下面的代码，

var t = [{email: "[e-mail]", first: "Joao", last: "Bastos", gender: "Male", phone: "3.51939e+11"},
      {email: "", first: undefined, last: undefined, gender: undefined, phone: undefined},
      {email: "[e-mail]", first: "Joao", last: "Bastos", gender: "Male", phone: undefined}];

var resultArray = t.filter((row) => {
    var ignoreValue = Object.values(row).some(elem => elem === undefined);
    return !ignoreValue ? true : false;
});
console.log(resultArray);