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bash - 在第二次出现另一个字符串后保留该字符串

问题描述

我有一个文件，其中包含如下所示的行：

username1
username2
./2011-05-25-0.json.gz:{"repo":{"url":"https://api.github.dev/repos//","name":"/"},"type":"FollowEvent","public":true,"created_at":"2011-05-25","payload":{"target":{"gravatar_id":"5e17","id":144929,"repos":12,"followers":1,"login":"username3"}},"actor":{"gravatar_id":"dec","id":21,"url":"https://api.github.dev/users/user","avatar_url":"https://secure.gravatar.com/avatar/decc?d=http://github.dev%2Fimages%2Fgravatars%2Fgravatar-user-420.png","login":"username4"},"id":"14"} 
./2011-05-25-0.json.gz:{"repo":{"url":"https://api.github.dev/repos//","name":"/"},"type":"FollowEvent","public":true,"created_at":"2011-05-25","payload":{"target":{"gravatar_id":"f9ed","id":82,"repos":5,"followers":4,"login":"username5"}},"actor":{"gravatar_id":"decc93","id":21,"url":"https://api.github.dev/users/username","avatar_url":"https://secure.gravatar.com/avatar/de?d=http://github.dev.user-420.png","login":"username6"},"id":"147"}

我想获得一个文件，其中包含：

username1
username2
username4
username6

也就是说，如果字符串"login":出现在一行上，则"在第二次出现之后立即获取其中包含的字符串"login"。否则，保持线路不变。

我怎样才能做到这一点grep，或sed？

标签： bash

解决方案

你可以试试：

sed 's/.*{.*login":"\([^"]*\)".*/\1/g' text.txt

或者

sed -i.bkup 's/.*{.*login":"\([^"]*\)"}.*/\1/g' text.txt

用新用户名覆盖文件并将旧用户名 bkup 到 text.txt.bkup

注意：这假设用户名不包含正则表达式描述的模式。

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