python - 简单的 python else 函数不会运行,这将导致脚本结束
问题描述
secret_word = "Michael Jackson"
guess = ""
guess = 0
guess_limit = 5
out_of_guesses = False
guess_count = 0
while guess != secret_word and not (out_of_guesses):
if guess_count < guess_limit:
guess = input("Enter Guess:")
guess_count +=1
print("Famous Pop Star")
if guess_count < guess_limit:
guess = input("Enter Guess:")
guess_count += 1
print("Died a legend")
if guess_count < guess_limit:
guess = input("Enter Guess:")
guess_count += 1
print("Very Talented")
if guess_count < guess_limit:
guess = input("Enter Guess:")
guess_count += 1
print("Died in a bathtub")
if guess_count < guess_limit:
guess = input("Enter Guess:")
guess_count += 1
print("wore a plaid shirt" )
else:
out_of_guesses = True
if out_of_guesses:
print("You Lose....Answer was Michael Jackson")
else:
print("You Win! Your knowledge over music is very vast!")
最底层的 Else 函数不会运行,这将决定你是赢还是输。
解决方案
我不知道您是否了解过python indent
,但正如@JonathanK 所说,您遇到了关于 的问题if else
,实际上您的代码现在是错误的。这是我的建议代码,希望它能达到您的目的:
secret_word = "Michael Jackson"
guess = ""
# guess = 0
guess_limit = 5
out_of_guesses = False
guess_count = 0
while guess != secret_word and not (out_of_guesses):
guess = input("Enter Guess:")
if guess_count < guess_limit and guess != secret_word:
guess_count +=1
print("Famous Pop Star")
guess = input("Enter Guess:")
if guess_count < guess_limit and guess != secret_word:
guess_count += 1
print("Died a legend")
guess = input("Enter Guess:")
if guess_count < guess_limit and guess != secret_word:
guess_count += 1
print("Very Talented")
guess = input("Enter Guess:")
if guess_count < guess_limit and guess != secret_word:
guess_count += 1
print("Died in a bathtub")
guess = input("Enter Guess:")
if guess_count < guess_limit and guess != secret_word:
guess_count += 1
print("wore a plaid shirt" )
else:
out_of_guesses = True
if out_of_guesses:
print("You Lose....Answer was Michael Jackson")
else:
print("You Win! Your knowledge over music is very vast!")
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