json - 将最终转换为列表扑

Question

我有以下 JSON：

"cast": [
    {
      "cast_id": 0,
      "character": "John Wick",
      "credit_id": "591d49ad925141499001b005",
      "gender": 2,
      "id": 6384,
      "name": "Keanu Reeves",
      "order": 0,
      "profile_path": "/bOlYWhVuOiU6azC4Bw6zlXZ5QTC.jpg"
    },
    {
      "cast_id": 9,
      "character": "Sofia",
      "credit_id": "5b031331925141097301b798",
      "gender": 1,
      "id": 4587,
      "name": "Halle Berry",
      "order": 1,
      "profile_path": "/hdUqx0on0cqbFuJCZtEGU42UWe5.jpg"
    },
]

我有以下方法可以获取该 JSON 并将其传递给模型：

final respuesta=await http.get(url);
final decodedData=json.decode(respuesta.body);
final cast=new Cast.fromJSONMap(decodedData['cast']);

最后一行引用模型中的这个方法，从那里映射并保存数据：

Cast.fromJSONMap(List<dynamic> jsonList) {
    if (jsonList == null) return;

    for (var item in jsonList) {
      final actor = new Actor.fromJSONMap(item);
      actores.add(actor);
    }
  }

一切对我来说都很好

现在我有以下 JSON：

{
  "birthday": "1964-09-02",
  "known_for_department": "Acting",
  "deathday": null,
  "id": 6384,
  "name": "Keanu Reeves",
  "also_known_as": [
    "Киану Ривз",
    "كيانو ريفز",
    "키아누 리브스",
    "キアヌ・リーブス",
    "เคอานู รีฟส์",
    "基努·里维斯",
    "קיאנו ריבס",
    "Keanu Charles Reeves"
  ],
  "gender": 2,
  "biography": "XXXXXXXXXXXX",
  "popularity": 34.892,
  "place_of_birth": "Beirut, Lebanon",
  "profile_path": "/bOlYWhVuOiU6azC4Bw6zlXZ5QTC.jpg",
  "adult": false,
  "imdb_id": "nm0000206",
  "homepage": null
}

我想恢复它并像以前的那样映射它，但是这个 JSON 没有xxx: []像前面的例子那样包装它，因此，当使用相同的方法传递它来映射它时：

    final respuesta=await http.get(url);
    final decodedData=json.decode(respuesta.body);
    final person=new DetalleActor.fromJSONMap(decodedData);

与上一行一样的最后一行使用以下方法对其进行映射：

DetalleActor.fromJSONMap(List<dynamic> jsonList) {
    if (jsonList == null) return;

    for (var item in jsonList) {
      final persona = new Persona.fromJSONMap(item);
      personas.add(persona);
    }
  }

它向我显示以下错误：

_TypeError (type '_InternalLinkedHashMap<String, dynamic>' 
is not a subtype of type 'List<dynamic>')

据我说，这是因为他在等待类似的东西，decodedData[xxx]但我不知道如何解决。

标签： jsonflutter

Answer 1

另一种安全的方法：

class DetalleActor {
  final bool adult;
  final List<String> alsoKnownAs;
  final String biography;
  final String birthday;
  final Object deathday;
  final int gender;
  final Object homepage;
  final int id;
  final String imdbId;
  final String knownForDepartment;
  final String name;
  final String placeOfBirth;
  final double popularity;
  final String profilePath;

  DetalleActor(
      {this.adult,
      this.alsoKnownAs,
      this.biography,
      this.birthday,
      this.deathday,
      this.gender,
      this.homepage,
      this.id,
      this.imdbId,
      this.knownForDepartment,
      this.name,
      this.placeOfBirth,
      this.popularity,
      this.profilePath});

  factory DetalleActor.fromJson(Map<String, dynamic> json) {
    return DetalleActor(
      adult: json['adult'] as bool,
      alsoKnownAs: _toList(json['also_known_as'], (e) => e as String),
      biography: json['biography'] as String,
      birthday: json['birthday'] as String,
      deathday: json['deathday'],
      gender: json['gender'] as int,
      homepage: json['homepage'],
      id: json['id'] as int,
      imdbId: json['imdb_id'] as String,
      knownForDepartment: json['known_for_department'] as String,
      name: json['name'] as String,
      placeOfBirth: json['place_of_birth'] as String,
      popularity: _toDouble(json['popularity']),
      profilePath: json['profile_path'] as String,
    );
  }

  Map<String, dynamic> toJson() {
    return {
      'adult': adult,
      'also_known_as': _fromList(alsoKnownAs, (e) => e),
      'biography': biography,
      'birthday': birthday,
      'deathday': deathday,
      'gender': gender,
      'homepage': homepage,
      'id': id,
      'imdb_id': imdbId,
      'known_for_department': knownForDepartment,
      'name': name,
      'place_of_birth': placeOfBirth,
      'popularity': popularity,
      'profile_path': profilePath,
    };
  }
}

List _fromList(data, Function(dynamic) toJson) {
  if (data == null) {
    return null;
  }
  var result = [];
  for (var element in data) {
    var value;
    if (element != null) {
      value = toJson(element);
    }
    result.add(value);
  }
  return result;
}

double _toDouble(data) {
  if (data == null) {
    return null;
  }
  if (data is int) {
    return data.toDouble();
  }
  return data as double;
}

List<T> _toList<T>(data, T Function(dynamic) fromJson) {
  if (data == null) {
    return null;
  }
  var result = <T>[];
  for (var element in data) {
    T value;
    if (element != null) {
      value = fromJson(element);
    }
    result.add(value);
  }
  return result;
}

/*
DetalleActor:
  "birthday": String
  "known_for_department": String
  "deathday": Object
  "id": int
  "name": String
  "also_known_as": List<String>
  "gender": int
  "biography": String
  "popularity": double
  "place_of_birth": String
  "profile_path": String
  "adult": bool
  "imdb_id": String
  "homepage": Object
*/