首页 > 解决方案 > 将数据添加到现有模型,并将真实数据添加到 MVC

问题描述

我有一个先前的问题,显示了我的模型的外观以及添加了 FAKE 数据。 基于需要添加到 List<T> 的 POCO 添加到现有模型

现在我想添加真实数据,我想知道如何做到这一点。是否应该或需要我遍历result??

public IActionResult FindPerson (FindPersonViewModel findPersonViewModel)
{
    var firstName = findPersonViewModel.FirstName;
    var middleName = findPersonViewModel.MiddleName;
    var lastName = findPersonViewModel.LastName;
    var emailAddress = findPersonViewModel.EmailAddress;
    var genderTypeId = findPersonViewModel.GenderTypeId;


    // GET REAL DATA 
    using (AzEdsIdentityContext context = new AzEdsIdentityContext(AzEdsIdentityContext.Options))
    {
         var result = context.FindPerson(firstName, lastName, genderTypeId);

         // for loop on the result to hydrate new List<FindPersonResultsViewModel>()  ?         

    }


   // Note:  here is exactly how I hydrated the model with fake data

   findPersonViewModel.findPersonResultsViewModel = new List<FindPersonResultsViewModel>()
                { new FindPersonResultsViewModel { AZEDID = 33423432, PersonID = 3534454, FirstName = "John", LastName = "Williamson", MiddleName = "K", ExistInContactManager = false, ActionType = true, ContactType = "Principal", DOB = "5/1/1985", PhysicalAddress = "123 main st. mesa, az.", PreferredEmail = "john@aol.com", PreferredPhone = "602-393-4443"},
                  new FindPersonResultsViewModel { AZEDID = 33423432, PersonID = 3534454, FirstName = "Jon", LastName = "Williamson", MiddleName = "K", ExistInContactManager = false, ActionType = true, ContactType = "Principal", DOB = "5/1/1985", PhysicalAddress = "123 main st. mesa, az.", PreferredEmail = "john@aol.com", PreferredPhone = "602-393-4443"},
   };


}

标签: c#asp.netlistasp.net-coreviewmodel

解决方案


给定 Person 模型

public class Person
{
    public int Id { get; set; }
    public string Name { get; set; }
    public string Email { get; set; }
}

你从你的上下文中获得结果

List<Person> result = context.getPersons();

您需要一个不同但相似类型的集合,因此您使用投影

List<PersonViewModel> result =
    context.getPersons()
           .Select(p => new FindPersonResultsViewModel
                            {
                                Name = p.Name,
                                Email = p.Email
                            }).ToList();

然后将集合属性分配给另一个模型

var model = new ResultViewModel
                {
                    ...
                    findPersonResultsViewModel = result
                };

如果您要返回 IEnumerable,请务必.ToList()获取List<T>.


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