首页 > 解决方案 > 如何使用函数检查数字来解决字符串中的字母、符号、数字计数问题

问题描述

我想使用函数密码计算字母、数字、符号似乎它没有正确计算数字,因为最后每个 printf 都得到 0

#include <stdio.h>
void password(char * str[],int together,int numbers,int symbols,int i,int uppercase,int lowercase);
int main()
{
    char str[100];
    int together, numbers, symbols, i,uppercase,lowercase;

        together = numbers = symbols = i = uppercase = lowercase = 0;

    printf("password : ");
    gets(&str);
    printf(" %s", str);
    password(&str,together,numbers,symbols,i,uppercase,lowercase);
    printf("Number of letters = %d\n", together);
    printf("number uppercase  = %d\n", uppercase);
    printf("Number lowecase  = %d\n", lowercase);
    printf("numbers = %d\n", numbers);
    printf("Simboli = %d", symbols);
if (together >= 8 && numbers >= 2){
    printf("\nPassword is correct");
}else{
    printf("\nPassword isn't correct");
}
    return 0;
}
void password(char * str[],int together,int numbers,int symbols,int i,int uppercase,int lowercase){
     while(*str[i]!='\0')
    {
        if((*str[i]>='a' && *str[i]<='z') || (*str[i]>='A' && *str[i]<='Z'))
        {
            together++;
        }
        else if(*str[i]>='0' && *str[i]<='9')
        {
            numbers++;
        }
        else if(*str[i] >= 'A' && *str[i] <= 'Z') {
         uppercase++;
        }
        else if(*str[i] >= 'a' && *str[i] <= 'z'){
            lowercase++;
        }
        else
        {
            symbols++;
        }

        i++;
    }
}

每个数字、字母和符号程序运行时我都得到零,没有任何错误我尝试更改一些东西,但我目前正在学习 C,所以这对我来说很难!

标签: c

解决方案


几点:1)不需要传递 i 作为参数,因为您可以使用strlenfrom获取字符串的长度string.h(返回size_t类型而不是int)。2)您将参数作为值传递,这意味着它们只会在本地更改为您的函数。3)不要使用不安全的gets函数,你可能要使用fgetsor scanf

#include <string.h>
#include <stdio.h>

void password(char *str, int *together, int *numbers, int *symbols, int *uppercase, int *lowercase){
    for(size_t i=0; i<strlen(str); i++){
        if(str[i] >= '0' && str[i] <= '9') (*numbers)++;
        if(str[i] >= 'A' && str[i] <= 'Z') (*uppercase)++;
        if(str[i] >= 'a' && str[i] <= 'z') (*lowercase)++;
        if(str[i] >= '!' && str[i] <= '/') (*symbols)++;
    }
    *together = (*uppercase) + (*lowercase);
}

int main(void){

    char str[100] = "Pa$$w0/2d";
    int together = 0;
    int numbers = 0;
    int symbols = 0;
    int uppercase = 0;
    int lowercase = 0;

    password(str, &together, &numbers, &symbols, &uppercase, &lowercase);
    printf("Letters = %d\n", together);
    printf("Uppercase  = %d\n", uppercase);
    printf("Lowercase = %d\n", lowercase);
    printf("Numbers = %d\n", numbers);
    printf("Symbols = %d\n", symbols)

    return 0;
}

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