时间戳

首页 > 解决方案 > 如何在声明期间将操作分配给复数？

c++ - 如何在声明期间将操作分配给复数？

问题描述

我正在为复数编写一个类，当我声明其中一个时，我必须在我可以为其分配操作之前且仅在之后声明它。

例如：

这有效： 

ComplexNumber Number;  
Number = AnotherComplex + (or -) AgainAnotherComplex;

这不起作用： 

ComplexNumber Number = AnotherComplex + (or -) AgainAnotherComplex;

我留下的是 .h 文件：

#ifndef COMPLEX_NUMBERS_H_INCLUDED
#define COMPLEX_NUMBERS_H_INCLUDED

#include <iostream> // for std namespace

class ComplexNumber
{
    public:
        ComplexNumber();
        ComplexNumber(float RealPart, float ImaginaryPart);
        ComplexNumber(ComplexNumber &NewComplexNumber);
        ~ComplexNumber();
        void SetRealPart(float RealPart);
        void SetImaginaryPart(float ImaginaryPart);
        friend ComplexNumber operator+(const ComplexNumber Complex1, const ComplexNumber Complex2);
        friend ComplexNumber operator-(const ComplexNumber Complex1, const ComplexNumber Complex2);
        friend std::ostream & operator<<(std::ostream &output, const ComplexNumber &NumberToDsiplay);
        friend std::istream & operator >>(std::istream &input, ComplexNumber &NumberToInput);
        bool operator==(const ComplexNumber Complex);
        bool operator!=(const ComplexNumber Complex);

    private:
        float RealPart;
        float ImaginaryPart;
};

#endif // COMPLEX_NUMBERS_H_INCLUDED

我还把 .cpp 文件留在这里：

#include "Complex Numbers.h"

ComplexNumber::ComplexNumber()
{
    RealPart = 0;
    ImaginaryPart = 0;
}

ComplexNumber::ComplexNumber(float RealPart, float ImaginaryPart)
{
    SetRealPart(RealPart);
    SetImaginaryPart(ImaginaryPart);
}

ComplexNumber::~ComplexNumber()
{
}

ComplexNumber::ComplexNumber(ComplexNumber &NewComplexNumber)
{
    RealPart = NewComplexNumber.RealPart;
    ImaginaryPart = NewComplexNumber.ImaginaryPart;
}

void ComplexNumber::SetRealPart(float RealPart)
{
    this->RealPart=RealPart;
}

void ComplexNumber::SetImaginaryPart(float ImaginaryPart)
{
    this->ImaginaryPart=ImaginaryPart;
}

ComplexNumber operator+(const ComplexNumber Complex1, const ComplexNumber Complex2)
{
    ComplexNumber TemporaryComplexNumber;
    TemporaryComplexNumber.RealPart = Complex1.RealPart + Complex2.RealPart;
    TemporaryComplexNumber.ImaginaryPart = Complex1.ImaginaryPart + Complex2.ImaginaryPart;

    return TemporaryComplexNumber;
}

ComplexNumber operator-(const ComplexNumber Complex1, const ComplexNumber Complex2)
{
    ComplexNumber TemporaryComplexNumber;
    TemporaryComplexNumber.RealPart = Complex1.RealPart - Complex2.RealPart;
    TemporaryComplexNumber.ImaginaryPart = Complex1.ImaginaryPart - Complex2.ImaginaryPart;

    return TemporaryComplexNumber;
}


std::ostream & operator<<(std::ostream &output, const ComplexNumber &NumberToDsiplay)
{
    if(NumberToDsiplay.ImaginaryPart > 0)
        output << std::endl << NumberToDsiplay.RealPart << "+" << NumberToDsiplay.ImaginaryPart << "i";
    else if(NumberToDsiplay.ImaginaryPart < 0)
        output << std::endl << NumberToDsiplay.RealPart << "" << NumberToDsiplay.ImaginaryPart << "i";
    else if(NumberToDsiplay.ImaginaryPart == 0)
        output << std::endl << NumberToDsiplay.RealPart << "  (The imaginary part is equal to 0)";
    return output;
}

std::istream & operator >>(std::istream &input, ComplexNumber &NumberToInput)
{
    std::cout << "Enter the real part: ";
    input >> NumberToInput.RealPart;
    std::cout << "Enter the imaginary part: ";
    input >> NumberToInput.ImaginaryPart;
}

bool ComplexNumber::operator==(const ComplexNumber Complex)
{
    return RealPart==Complex.RealPart && ImaginaryPart==Complex.ImaginaryPart;
}

bool ComplexNumber::operator!=(const ComplexNumber Complex)
{
    if(RealPart != Complex.RealPart && ImaginaryPart != Complex.ImaginaryPart)
            return true;
    else if(RealPart != Complex.RealPart && (!(ImaginaryPart != Complex.ImaginaryPart)))
            return true;
    else if(ImaginaryPart != Complex.ImaginaryPart && (!(RealPart != Complex.RealPart)))
        return true;

    return false;
}

标签： c++referenceoperator-overloadingcopy-constructorcomplex-numbers

解决方案

只需声明复制构造函数

ComplexNumber( const ComplexNumber &NewComplexNumber);
               ^^^^^

否则，编译器无法将非常量引用绑定到作为表达式结果的临时引用

AnotherComplex + (or -) AgainAnotherComplex

调用任一运算符

    friend ComplexNumber operator+(const ComplexNumber Complex1, const ComplexNumber Complex2);
    friend ComplexNumber operator-(const ComplexNumber Complex1, const ComplexNumber Complex2);

反过来应该声明为

    friend ComplexNumber operator+(const ComplexNumber &Complex1, const ComplexNumber &Complex2);
    friend ComplexNumber operator-(const ComplexNumber &Complex1, const ComplexNumber &Complex2);

那就是参数应该是引用类型。

而这个运算符定义

bool ComplexNumber::operator!=(const ComplexNumber Complex)
{
    if(RealPart != Complex.RealPart && ImaginaryPart != Complex.ImaginaryPart)
            return true;
    else if(RealPart != Complex.RealPart && (!(ImaginaryPart != Complex.ImaginaryPart)))
            return true;
    else if(ImaginaryPart != Complex.ImaginaryPart && (!(RealPart != Complex.RealPart)))
        return true;

    return false;
}

没有多大意义。

像这样定义

bool ComplexNumber::operator!=(const ComplexNumber &Complex) const
{
    return not( *this == Complex );
}

注意const参数列表后面的限定符。您需要添加到operator ==.

推荐阅读