首页 > 解决方案 > csv文件的Integer.parseInt在Java中不起作用

问题描述

我试图将 csv 文件中的信息读入 eclipse,然后将每列读入相应的变量,但我不断收到此错误。我看到错误可能发生在这行代码

int accountNUM = Integer.parseInt(values[0]);

我得到的错误如下

Exception in thread "main" java.lang.NumberFormatException: For input string: "1;PhilJohnston;phil.johnston@gmail.com;"
    at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.base/java.lang.Integer.parseInt(Integer.java:652)
    at java.base/java.lang.Integer.parseInt(Integer.java:770)
    at Verbindung.main(Verbindung.java:55)

当我将“,”更改为“;”时 我收到以下错误

线程“主”java.lang.ArrayIndexOutOfBoundsException 中的异常:索引 0 超出 Verbindung.main 处长度 0 的范围(Verbindung.java:55)

我的 csv 文件是这种格式

A            b               c
1        PhilJohnston     phil.johnston@gmail.com 

对应的Java代码

import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
import java.sql. * ;
import oracle.jdbc.driver. * ;

import java.text.ParseException;
import java.text.SimpleDateFormat;

public class Verbindung {

    public static void main(String[] args) {

        //Importing CSV File for table FUSER
        String filename = "Fuser_excel.csv";
        File file = new File(filename);

        // Creating Arraylist
        ArrayList < FBuser > fuser = new ArrayList < FBuser > ();
        //  ArrayList<Suppliers> lieferant = new ArrayList<Suppliers>();
        //ArrayList<Delivery> lieferung = new ArrayList<Delivery>();

        try {
            Scanner inputStream = new Scanner(file);
            while (inputStream.hasNext()) {
                String data = inputStream.next();
                String[] values = data.split(",");
                int accountNUM = Integer.parseInt(values[0]);
                String N_AME = values[1];
                //String EMAIL = values[2];
                //System.out.println(accountNUM);
                //creating the object FBuser with the relevant parameters
                //FBuser fbuser = new FBuser(accountNUM,N_AME,EMAIL);
                //fuser.add(fbuser);
            }
            inputStream.close();
        }
        catch(FileNotFoundException d) {
            d.printStackTrace();
        }

        try {
            // establish connection to database
            Class.forName("oracle.jdbc.driver.OracleDriver");
            String database = "jdbc:oracle:thin:@oracle-lab.cs.univie.ac.at:1521:lab";
            String user = "a01547605";
            String pass = "dbs19";

            // establish connection to database 
            Connection con = DriverManager.getConnection(database, user, pass);
            Statement stmt = con.createStatement();

            String sql = "INSERT into fuser (accountNUM, N_AME, EMAIL) values(?,?,?)";
            PreparedStatement ps = con.prepareStatement(sql);

            final int batchSize = 1000;
            int count = 0;
            for (FBuser a: fuser) {
                ps.setInt(1, a.getaccountNUM());
                ps.setString(2, a.getN_AME());
                ps.setString(3, a.getEMAIL());
                ps.addBatch();

                if (++count % batchSize == 0) {
                    ps.executeBatch();
                }
            }
            ps.close();
        }
        catch(Exception e) {
            System.err.println(e.getMessage());
        }
    }
}

the corresponding Class
public class FBuser {
    int accountNUM;  
    String N_AME;
    String EMAIL;

    public FBuser(int accountNUM,String N_AME, String EMAIL ) {
        this.accountNUM = accountNUM;
        this.N_AME = N_AME;
        this.EMAIL = EMAIL;
    }

    public int getaccountNUM() {
        return accountNUM;
    }

    public String getN_AME() {
        return N_AME;
    }

    public String getEMAIL() {
        return EMAIL;
}
}

我不明白我哪里出错了。csv 文件本身可能存在问题,或者只是读取方式存在问题。

标签: javacsv

解决方案


根据您作为 CSV 文件发布的内容,存在两个问题。首先,您的分隔符不是逗号,而是空格。其次,如果您更改为空格作为分隔符,则第一个值(值 [0])将为“A”。Java 无法将“A”转换为数字。


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