python - 熊猫在使用 dataframe.shift() 时表现得很奇怪

Question

我正在阅读一些看起来像这样的数据：

在此数据集中，第 16 列中有许多行null。我需要将这些行中的值向右移动，以便以“*”开头的值（例如，第 16 列第 4 行，第 13 列第 5 行等） ) 将移动到它们右侧的列。（最终我将在一个循环中执行此操作，以便这些值将进入第 16 列）。

这些值左侧的数据也必须移动。例如，当 {column 7 row 16} 中的数据移动到 {column 8, row 16} 时，{column 2 row 16} 中的数据应该移动到 {column 3 row 16}。

但是，我不希望第 1 列（零索引第 0 列）中的数据移动，因为我将使用它作为我的数据的索引。

因此我的预期输出是这样的：

我正在使用下面的代码来实现这一点：

import StringIO
import pandas

# Store the csv string in a variable and turn that into a dataframe
# This string here is the same as the data in the image above.
gps_string = """2010-01-12 18:00:00,$GPGGA,180439,7249.2150,N,11754.4238,W,2.0,10,0.9,-8.1,M,-12.4,M,,*57,,,
2010-01-12 17:30:00,$GPGGA,173439,7249.2160,N,11754.4233,W,2.0,11,0.8,-4.5,M,-12.4,M,,*5B,,,
2010-01-12 17:00:00,$GPGGA,170439,7249.2152,N,11754.4235,W,2.0,11,0.8,-3.1,M,-12.4,M,,*5C,,,
2010-01-12 16:30:00,N,11754.4210,W,2,9.0,1.1,-13.1,M,-12.4,M,,*6C,,,,,,
2010-01-12 16:00:00,N,11754.4229,W,2,10.0,0.9,-2.9,M,-12.4,M,,*53,,,,,,
2010-01-12 15:30:00,N,11754.4269,W,2,9.0,0.8,-4.3,M,-12.4,M,,*54,,,,,,
2010-01-12 15:00:00,N,11754.4267,W,2,10.0,0.8,-1.6,M,-12.4,M,,*56,,,,,,
2010-01-12 14:30:00,$GPGGA,143439,7249.2152,N,11754.4253,W,2.0,11,0.7,-4.3,M,-12.4,M,,*56,,,
2010-01-12 14:00:00,N,11754.4245,W,2,10.0,0.9,-7.0,M,-12.4,M,,*50,,,,,,
2010-01-12 13:30:00,$GPGGA,133439,7249.2134,N,11754.4243,W,2.0,11,0.7,-10.7,M,-12.4,M,,*61,,,
2010-01-12 13:00:00,N,11754.4245,W,2,10.0,0.8,-5.5,M,-12.4,M,,*56,,,,,,
2010-01-12 12:30:00,N,11754.4226,W,2,10.0,0.9,-7.1,M,-12.4,M,,*59,,,,,,
2010-01-12 12:00:00,N,11754.4238,W,2,10.0,0.8,-6.5,M,-12.4,M,,*51,,,,,,
2010-01-12 11:30:00,N,11754.4227,W,2,10.0,0.8,0.1,M,-12.4,M,,*73,,,,,,
2010-01-12 11:00:00,-7.4,M,-12.4,M,,*5F,,,,,,,,,,,,
2010-01-12 10:30:00,N,11754.4271,W,2,8.0,1.1,-8.4,M,-12.4,M,,*5A,,,,,,
""" 
# Read the csv string into a dataframe, with no headers
# Make the first column with timestamp values the index column.
gps_df = pd.read_csv(StringIO.StringIO(gps_string), header=None, 
index_col=0)
rows_to_shift = gps_df[gps_df[15].isnull()].index

# Shift the rows here.
gps_df.loc[rows_to_shift] = gps_df.loc[rows_to_shift].shift(periods=1, axis=1)
gps_df.to_csv("f.csv") # Creates a file after shift to see the output

执行代码时，我得到以下输出文件。

从这里我看到 shift 函数null(s)出于某种原因在第 5 列创建了一列，并且它还将最初在第 10 列中的数据移动到第 15 列，知道为什么会这样吗？

这可能是dataframe.shift()函数中的错误吗？还是我在这里做错了什么？

标签： pythonpandasdataframe

Answer 1

这是 pandas 中的一个错误，可以在此处找到更多详细信息。

似乎移动对象列将自动转移到具有对象 dtype 的下一列。

为了解决这个问题，我选择了要移动的索引，将数据框中的所有数据转换为字符串，执行移动，再次将数据作为 csv 字符串获取，然后重新创建数据框以获取以前的数据类型.

以下是我用来解决此问题的代码：

import pandas as pd
import StringIO

gps_string = """
"2010-01-12 18:00:00","$GPGGA","180439","7249.2150","N","11754.4238","W","2","10","0.9","-8.1","M","-12.4","M","","*57","","",""
"2010-01-12 17:30:00","$GPGGA","173439","7249.2160","N","11754.4233","W","2","11","0.8","-4.5","M","-12.4","M","","*5B","","",""
"2010-01-12 17:00:00","$GPGGA","170439","7249.2152","N","11754.4235","W","2","11","0.8","-3.1","M","-12.4","M","","*5C","","",""
"2010-01-12 16:30:00","N","11754.4210","W","2","09","1.1","-13.1","M","-12.4","M","","*6C","","","","","",""
"2010-01-12 16:00:00","N","11754.4229","W","2","10","0.9","-2.9","M","-12.4","M","","*53","","","","","",""
"2010-01-12 15:30:00","N","11754.4269","W","2","09","0.8","-4.3","M","-12.4","M","","*54","","","","","",""
"2010-01-12 15:00:00","N","11754.4267","W","2","10","0.8","-1.6","M","-12.4","M","","*56","","","","","",""
"2010-01-12 14:30:00","$GPGGA","143439","7249.2152","N","11754.4253","W","2","11","0.7","-4.3","M","-12.4","M","","*56","","",""
"2010-01-12 14:00:00","N","11754.4245","W","2","10","0.9","-7.0","M","-12.4","M","","*50","","","","","",""
"2010-01-12 13:30:00","$GPGGA","133439","7249.2134","N","11754.4243","W","2","11","0.7","-10.7","M","-12.4","M","","*61","","",""
"2010-01-12 13:00:00","N","11754.4245","W","2","10","0.8","-5.5","M","-12.4","M","","*56","","","","","",""
"2010-01-12 12:30:00","N","11754.4226","W","2","10","0.9","-7.1","M","-12.4","M","","*59","","","","","",""
"2010-01-12 12:00:00","N","11754.4238","W","2","10","0.8","-6.5","M","-12.4","M","","*51","","","","","",""
"2010-01-12 11:30:00","N","11754.4227","W","2","10","0.8","0.1","M","-12.4","M","","*73","","","","","",""
"2010-01-12 11:00:00","-7.4","M","-12.4","M","","*5F","","","","","","","","","","","",""
"2010-01-12 10:30:00","N","11754.4271","W","2","08","1.1","-8.4","M","-12.4","M","","*5A","","","","","",""

 """

gps_df = pd.read_csv(StringIO.StringIO(gps_string), header=None, index_col=0)
rows_to_shift = gps_df[gps_df[15].isnull()].index  # get the indexes to shift
gps_df_all_strings = gps_df.astype(str)  # Convert all the data to be of type str (string)

# Shift the data
gps_df_all_strings.loc[rows_to_shift] = gps_df_all_strings.loc[rows_to_shift].shift(periods=1, axis=1)
s = gps_df_all_strings.to_csv(header=None)  # Put shifted csv data into a string after shifting.
new_gps_df = pd.read_csv(StringIO.StringIO(s), header=None, index_col=0)  # re read csv data.