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c# - 删除根节点但保留所有子节点

问题描述

我有这个通过解析的 xml

<ns0:Root xmlns:ns0="http://Core.Schemas.SouCurrencyRate">
    <Test>
        <CurrencyCode>SEKAUDPMI</CurrencyCode>
        <CurrencyType>AUD</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>6.5656</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
    <Test>
        <CurrencyCode>SEKBRLPMI</CurrencyCode>
        <CurrencyType>BRL</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>2.4376</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
    <Test>
        <CurrencyCode>SEKCADPMI</CurrencyCode>
        <CurrencyType>CAD</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>7.0771</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
    <Test>
        <CurrencyCode>SEKCHFPMI</CurrencyCode>
        <CurrencyType>CHF</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>951.7346</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
</ns0:Root>

xml 有（“测试”）子节点发生了很多时间。我需要做的实际上是删除(" <ns0:Root xmlns:ns0="http://Core.Schemas.SouCurrencyRate"> ")

所以 XML 输出是

<Test>
    <CurrencyCode>SEKAUDPMI</CurrencyCode>
    <CurrencyType>AUD</CurrencyType>
    <CurrencyDate>2019 Juni</CurrencyDate>
    <CurrencyRate>6.5656</CurrencyRate>
    <RecordCreated>2019-06-30</RecordCreated>
    <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
</Test>
<Test>
    <CurrencyCode>SEKBRLPMI</CurrencyCode>
    <CurrencyType>BRL</CurrencyType>
    <CurrencyDate>2019 Juni</CurrencyDate>
    <CurrencyRate>2.4376</CurrencyRate>
    <RecordCreated>2019-06-30</RecordCreated>
    <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
</Test>

我试图做的是

    System.Xml.XmlDocument xDoc = new System.Xml.XmlDocument();
    xDoc.Load(bizobj.Message.BodyPart.GetOriginalDataStream());


    System.Xml.XmlNode xNode = xDoc.FirstChild;
    System.Xml.XmlNode xParent = xNode.ParentNode;
    System.Xml.XmlNodeList xChilds = xNode.ChildNodes;
    xDoc.RemoveChild(xNode);
    foreach (System.Xml.XmlNode node in xChilds)
    {
        xParent.AppendChild(node);
    }

但主要问题是返回的 xml 只包含一个孩子（“测试”）而不包含其他孩子。

我也尝试过使用 Linq，我在帖子中找到了这个

XDocument input = XDocument.Load("input.xml");
XElement firstChild = input.Root.Elements().First();

但这会返回相同的内容，并且对我的情况没有帮助。

有人可以帮助我朝着正确的方向前进吗？

谢谢。

标签： c#xmllinq-to-xmlelementxmldocument

解决方案

如果您真的只需要文本字符串，实现此目的的最快方法是在RootXElement 上使用 XmlReader：

XDocument xDoc = XDocument.Parse(bizobj.Message.BodyPart.GetOriginalDataStream());
XElement root = xDoc.Root;
XmlReader reader = root.CreateReader();
reader.MoveToContent();
string txt = reader.ReadInnerXml();

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