mysql - 如何获取链接到外键值的 InnoDB 表名?
问题描述
我有多个表(例如:A、B、C....等带有外键 ADDRESS_ID)链接到“地址”表,其中 ADDRESS_ID 是主键。表 A、B、C... 可能有或没有 address_ID 值。是否有一个查询可以让我在地址表中获取具有给定 ADDRESS_ID 的表名?请注意,这不是“地址”表中给定列的表名。如果在其他表中已经引用了地址表中给定的Address_ID 值,我需要表名。(我不知道所有可能引用了 address_id 的表。)
Address table
ADDRESS_ID (PK) | STREET ADDRESS_1 | STREET_ADDRESS_2 | CITY | ZIPCODE
Table A
A_ID | ADDRESS_ID (FK) | FIELD _1 | FIELD_2
Table B
B_ID | ADDRESS_ID (FK)| FIELD _! | FIELD_2
Table C
B_ID | ADDRESS_ID (FK) | FIELD _! | FIELD_2
更多表......
这是我尝试过的:
SELECT * FROM information_schema.TABLE_CONSTRAINTS
WHERE
information_schema.TABLE_CONSTRAINTS.CONSTRAINT_TYPE = 'FOREIGN KEY' AND
TABLE_CONSTRAINTS.TABLE_SCHEMA = 'flower_db' AND
TABLE_CONSTRAINTS.TABLE_NAME = 'address';
但这不支持我真正想要的。
解决方案
SELECT 'TableA' as Table_Has_Address
FROM TableA
GROUP BY ADDRESS_ID
HAVING COUNT(CASE WHEN ADDRESS_ID = @address_id THEN 1 END) > 0
UNION ALL
SELECT 'TableB' as Table_Has_Address
FROM TableB
GROUP BY ADDRESS_ID
HAVING COUNT(CASE WHEN ADDRESS_ID = @address_id THEN 1 END) > 0
UNION ALL
SELECT 'TableC' as Table_Has_Address
FROM TableC
GROUP BY ADDRESS_ID
HAVING COUNT(CASE WHEN ADDRESS_ID = @address_id THEN 1 END) > 0