c++ - 尝试构建包装器测量函数调用时间的问题
问题描述
我正在实现一些数据结构,每个数据结构都支持一组命令,例如INSERT value
.
我使用了一个标记器来生成一个包含每个单词/值的向量。
我希望能够将每个函数调用所花费的时间输出到 .txt 文件,加上函数返回的内容(如果它确实返回了某些内容)。
例如,如果命令是INSERT AVLTREE 4
,我只想输出调用所avl.insert(4)
花费的时间。如果命令是SEARCH AVLTREE 4
,我想输出调用所avl.search(4)
花费的时间,以及它的结果(例如"SUCCESS"
或"FAILURE"
)。
以下代码可能有很多问题,但这是我想出的:
我制作了两个文件(.cpp/.hpp),其中包含以下自破解函数包装器,以及一个变体和一个结构:
// WRAPPER CPP
// file: wrap.cpp
#include "wrap.hpp"
#include <chrono>
#include <string>
#include <utility>
#include <boost/variant.hpp>
using std::chrono::high_resolution_clock;
using std::chrono::time_point;
using std::chrono::nanoseconds;
using std::string;
using std::to_string;
using std::forward;
using boost::get;
using boost::static_visitor;
using boost::apply_visitor;
// I'm overloading std::to_string, so it works on std::strings as well.
string to_string(const string &value)
{
return value;
}
// I want to apply to_string on whatever is inside my variant.
class to_string_visitor : public static_visitor<>
{
public:
template <typename T>
void operator()(T & operand) const
{
to_string(operand);
}
};
// Takes two points in time and returns the time
// between them in nanoseconds.
const nanoseconds::rep duration(const nanoseconds tpoints_difference) noexcept
{
const auto result = tpoints_difference.count();
return result;
}
// Generates a point in time.
const high_resolution_clock::time_point timeNow(void) noexcept
{
const auto result = high_resolution_clock::now();
return result;
}
// Here's where's the problematic magic happens:
// The ret boolean is set to true if the function F returns a value,
// otherwise, it is set to false.
//
// Variadic arguments are being taken and then std::forwarded to F.
template<typename F, typename... Args>
const output wrapper(bool ret, F function, Args&&... args) noexcept
{
// Generate a point in time, t1.
const high_resolution_clock::time_point t1 = timeNow();
// If F returns a result,
if (ret == true)
{
// assign it to result (my variant).
result = function(forward<Args>(args)...);
}
else
{
// just call F with Args forwarded.
function(forward<Args>(args)...);
}
// Generate another point in time, t2 and
// count the difference between t2 - t1.
const auto elapsed = duration(timeNow() - t1);
// Make whatever is inside result a string
// using std::to_string.
apply_visitor(to_string_visitor(), result);
// My struct
output out;
// which contains the time elapsed and
// the result returned
out.time = elapsed;
out.result = get<string>(result);
// I can theoretically use both time elapsed and
// result returned however I want. Hooray!..almost:(
return out;
}
这是变体result
:
// These are all the types a data structure function may return.
variant<int, unsigned, uint32_t, size_t, graph_size, string> result = 0;
graph_size
,仅供参考:
struct graph_size
{
unsigned vertices; //Number of vertices that the Graph currently contains
unsigned edges; //Number of edges that the Graph currently contains
};
最后,output
结构:
typedef struct output
{
double time; // function call time
string result; // what function returned
// notice that if function returned nothing,
// result will be an empty string.
output() : time(0), result("") {}
} output;
我正在尝试wrapper
像这样使用:
AVL avl;
// stuff
auto out = wrapper(true, avl.insert, 4);
我收到以下错误:
invalid use of non-static member function 'void AVL::insert(int)'
这是一个奖励,它应该暗示我对我的拙劣但不能完全理解它:
no matching function for call to 'wrapper(bool, <unresolved overloaded function type>, unsigned int&)'
有什么想法吗?
我感谢所有提前花费的时间:)
编辑1:问题标题可能不太合适,如果你有好的想法,我会很高兴地改变
解决方案
由于您需要根据返回类型的不同行为,您可以使用专业化/SFINAE,例如:
template<typename F, typename... Args>
auto wrapper(F function, Args&&... args) noexcept
-> std::enable_if_t<std::is_same<void, std::invoke_result_t<F, Args&&...>>::value, output>
{
const high_resolution_clock::time_point t1 = timeNow();
function(forward<Args>(args)...);
const auto elapsed = duration(timeNow() - t1);
output out;
out.time = elapsed;
out.result = ""; // void return
return out;
}
template<typename F, typename... Args>
auto wrapper(F function, Args&&... args) noexcept
-> std::enable_if_t<!std::is_same<void, std::invoke_result_t<F, Args&&...>>::value, output>
{
const high_resolution_clock::time_point t1 = timeNow();
auto result = function(forward<Args>(args)...);
const auto elapsed = duration(timeNow() - t1);
output out;
out.time = elapsed;
out.result = to_string(result);
return out;
}
可能的用法:
AVL avl;
auto out = wrapper([&](){ return avl.insert(4);});
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