首页 > 解决方案 > 按特定值更改 Arraylist 顺序

问题描述

我有json对象类型arraylist,jsonobject包含字符串和布尔值。现在我的要求是设置arraylist以使其具有真实值。获取顶部包含真实值的所有jsonobject。那么我怎样才能通过特定值更改arraylist顺序. 假设我有 {matched:true},{matched:false},{matched:true},{matched:false},{matched:false},{matched:true} 的列表。但我想要列表 {matched: true},{matched:true},{matched:true},{matched:false},{matched:false},{matched:false}。使用语言 java。

标签: javaandroidandroid-json

解决方案


在科特林:

val list = arrayListOf(false, true, false, true, false)
    list.sortBy { it == false }

输出:

[true, true, false, false, false]

下面是一个例子,如果我们想从一个对象中排序:

// Your model class
class SomeObject(var value: String, var state: Boolean)
...

val list = arrayListOf<SomeObject>(
        SomeObject("some value", false),
        SomeObject("some value2", true),
        SomeObject("some value3", false),
        SomeObject("some value4", false),
        SomeObject("some value5", true))

    list.sortBy { it.state == false }

在 Java 中:

// Model -> 

public class SomeObject {

private String name;
private Boolean state;

public SomeObject(String name, Boolean state) {
    this.name = name;
    this.state = state;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public Boolean getState() {
    return state;
}

public void setState(Boolean state) {
    this.state = state;
}
}

...
    ArrayList<SomeObject> list = new ArrayList<>();
    list.add(new SomeObject("some value", false));
    list.add(new SomeObject("some value2", true));
    list.add(new SomeObject("some value3", false));
    list.add(new SomeObject("some value4", false));
    list.add(new SomeObject("some value5", true));

    list.sort((o1, o2) -> Boolean.compare(!o1.getState(), !o2.getState()));
    list.forEach((it) -> System.out.println(it.getState()));

输出:

[true, true, false, false, false]

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