javascript - 如何根据日期过滤数据?
问题描述
我有一个数组,
var data = [
{ id: 1, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2017-05-01]" },
{ id: 2, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2018-01-01]" },
{ id: 3, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2019-01-01]" },
{ id: 4, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2017-05-01]" },
{ id: 5, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2018-01-01]" },
{ id: 6, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2019-01-01]" },
{ id: 7, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2018-01-01]" },
{ id: 8, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2019-01-01]" },
{ id: 9, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2017-05-01]" }
];
data.forEach(function(result) {
console.log(result.jobCategoryWithFromDate);
});
这在控制台中给出了上述结果..
在 foreach 里面,我需要返回jobCategoryWithFromDate
最新日期的。
所以预期的结果是,(如下所示)..
ASSIST.. / Assistance [valid from 2019-01-01]
PROF.. / Professional [valid from 2019-01-01]
SEN.. / Senior [valid from 2019-01-01]
以上是预期的结果,没有任何变化,只需要过滤结果并返回jobCategoryWithFromDate
具有最新日期的唯一值..
尽管名称重复,但过滤器需要根据日期(最新)处理。
编辑:
我已经接受了答案,但后来我才知道它在所有情况下都不起作用,很抱歉没有完全测试它..
不知道我的解释是否出错,但如果用户名相同,则需要根据日期进行过滤,否则需要显示任何日期的唯一用户。
例如:
var data = [
{ id: 1, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2017-05-01]" },
{ id: 2, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2018-01-01]" },
{ id: 3, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2019-01-01]" },
{ id: 4, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2017-05-01]" },
{ id: 5, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2018-01-01]" },
{ id: 6, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2019-01-01]" },
{ id: 7, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2018-01-01]" },
{ id: 8, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2019-01-01]" },
{ id: 9, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2017-05-01]" },
{ id: 10, jobCategoryWithFromDate: "Jun.. / Junior [valid from 2018-01-01]" },
{ id: 11, jobCategoryWithFromDate: "Usr.. / User [valid from 2019-01-01]" },
{ id: 12, jobCategoryWithFromDate: "Man.. / Manager [valid from 2017-05-01]" }
];
function extractDate(string){
return string.match(/[0-9]+-[0-9]+-[0-9]+/g);
}
var result = data.reduce((newestDates, currentItem)=>{
if (newestDates.length===0) newestDates.push(currentItem);
else {
const dateDifference = new Date(extractDate(newestDates[0].jobCategoryWithFromDate)) - new Date(extractDate(currentItem.jobCategoryWithFromDate));
if (dateDifference===0) newestDates.push(currentItem); // push items with the same date as newest found
else if (dateDifference <= 0) newestDates = [currentItem]; // if item has newer date the original array gets replaced with one containing just this item
// ignore case dateDifference >= 0 because we do not need to do anything with dates older than the newest found
}
return newestDates;
},[]);
console.log(result);
在此代码段中,查看最后三个值,它们具有不同的用户名,但与以前的记录具有相同的日期。
这里的预期结果是我需要获取所有最后三个记录以及以上三个记录,因为它们是不同的用户,比如
ASSIST.. / Assistance [valid from 2019-01-01]
PROF.. / Professional [valid from 2019-01-01]
SEN.. / Senior [valid from 2019-01-01]
Jun.. / Junior [valid from 2018-01-01]
Usr.. / User [valid from 2019-01-01]
Man.. / Manager [valid from 2017-05-01]
解决方案
我会先找到最新的日期,然后过滤数组以查找具有此日期的对象。这将只返回日期最高的对象:
var data = [
{ id: 1, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2017-05-01]" },
{ id: 2, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2018-01-01]" },
{ id: 3, jobCategoryWithFromDate: "ASSIST.. / Assistance [valid from 2019-01-01]" },
{ id: 4, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2017-05-01]" },
{ id: 5, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2018-01-01]" },
{ id: 6, jobCategoryWithFromDate: "PROF.. / Professional [valid from 2019-01-01]" },
{ id: 7, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2018-01-01]" },
{ id: 8, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2019-01-01]" },
{ id: 9, jobCategoryWithFromDate: "SEN.. / Senior [valid from 2017-05-01]" }
];
/* Add new property to data objects to store the "valid from" timestamp - Avoids parsing the text twice */
data.forEach(function(element, index, array) {
var dateText = element.jobCategoryWithFromDate.match(/\[valid from (\d{4}-\d{2}-\d{2})\]$/)[1];
array[index].fromDateTimestamp = +(new Date(dateText));
});
/* Get the highest value (the latest date) */
var max = data.reduce(function(currentMax, value) {
return Math.max(currentMax, value.fromDateTimestamp);
}, 0);
/* Filter the data array to only include objects with the latest date */
var newData = data.filter(function(value) {
return value.fromDateTimestamp === max;
});
console.log(newData);
推荐阅读
- postgresql - 查询IP地址是否在表中startIP和EndIp列的范围内
- css - 如何从 max(env(safe-area-inset-bottom)) 声明 css 回退
- wordpress - 如何在 wordpress 上删除 https://sitename.com/sitename 页面?
- swift - 更改字典数组中的值 swift 5
- java - 如何修复“预期的 URL 方案 'http' 或 'https' 但未找到冒号”错误?
- javascript - 在 Bokeh DataTable 错误中引用行/列的 JS 代码
- go - 如何在函数中添加一些行可变次数?
- java - 用于 JDK8 的 Rhino javascript JSR-223-wrapper 在哪里?
- alfresco - 在 Alfresco 中找不到类 org.alfresco.web.config.WebClientConfigBootstrap
- c# - 为什么 SaveFileDialog 包含韩文字符时会更改文件名?