首页 > 解决方案 > django 复制迁移表的模型名称

问题描述

当我迁移我的 django 2 模型时,它可以毫无问题地制作表格,但表格的名称是这样的:‌nameofmodel_nameofmodel !!! 例如 booking_booking !!! 这是我的代码:

    from django.db import models


# Create your models here.
class Booking(models.Model):
    user_id = models.CharField(max_length=50, null=True )
    operator_id = models.CharField(max_length=50, null=True )
    computed_net_price = models.CharField(max_length=50, null=True )
    final_net_price = models.CharField(max_length=50, null=True )
    payable_price = models.CharField(max_length=50, null=True )
    booking_status = models.CharField(max_length=50, null=True )
    guest_name = models.CharField(max_length=50, null=True )
    guest_last_name = models.CharField(max_length=50, null=True )
    guest_cellphone = models.CharField(max_length=50, null=True )
    from_date = models.DateTimeField(max_length=50, null=True )
    to_date = models.DateTimeField(max_length=50, null=True )
    is_removed = models.IntegerField(null=True )

这是我的序列化程序:

from rest_framework import serializers
from .models import Booking
class BookingSerializer(serializers.ModelSerializer):
     class Meta:
         model = Booking
         fields =(
             'user_id',
             'computed_net_price',
             'final_net_price',
             'payable_price',
             'booking_status',
             'booking_status',
             'guest_name',
             'guest_last_name',
             'guest_cellphone',
             'guest_cellphone',
             'guest_cellphone',
             'operator_id',
             'is_removed',
         )

那么django的标准命名是什么,如果我想以不同的方式拥有它并且我做得正确与否怎么办

标签: pythondjangomigration

解决方案


你可以这样:

class YourModel(models.Model):
    # first_field = ....
    # second_field = ....

    class Meta:
        db_table = 'table_name'

https://docs.djangoproject.com/en/2.2/topics/db/models/#meta-options


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