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php - 试图在 postcount 上对我的 foreach 循环结果进行排序

问题描述

尝试根据从 Invision powerboard API（论坛软件）获得的帖子计数对顶级海报进行排序。无法弄清楚如何对我的 foreach 循环的这个回声进行排序。

$curl = curl_init( $communityUrl . '/core/members/' );
curl_setopt_array( $curl, array(
    CURLOPT_RETURNTRANSFER  => TRUE,
    CURLOPT_HTTPAUTH    => CURLAUTH_BASIC,
    CURLOPT_USERPWD     => "{$apiKey}:"
    ) );
$response = curl_exec( $curl );
$data = json_decode($response, true);
$count = 0;
foreach($data as $member) {     
    if (is_array($member)) {
        foreach($member as $name) { 
            if($count > 4) 
                return;
            echo '<p class="top-member-p"><a href="'.$name['profileUrl'].'">'.ucfirst($name['name']).'</a> has '.$name['posts'] . ' posts</p>';
            $count++;
        }
    }
}

我希望按照他们的帖子数对结果进行排序，如下所示：

"Swaghetti has 34 posts"<br>
"Josh has 15 posts"<br>
"Test has 3 posts"<br>
"Testuser2 has 0 posts"

但相反，它是这样的：

"Swaghetti has 34 posts"<br>
"Testuser2 has 0 posts"<br>
"Test has 3 posts"<br>
"Josh has 15 posts"

标签： phparrayssortingforeach

解决方案

如果您没有其他选择来检索已排序的数据，您可以自己进行 - 使用usort()- 由您自己的函数排序。与其他posts值进行比较，并将它们相应地放置在数组中（如果应该向上移动则返回 1，如果应该向下移动则返回 -1）。

我还添加array_slice()了，因为你似乎只想要前 4 个元素（这样你只得到那些，不需要计数器）。

// Test-data, I guessed my way to your format to match the output from what you had in the question
$data = [
    [['name' => 'Testuser2', 'posts' => 0, 'profileUrl' => 'swag']],
    [['name' => 'Josh', 'posts' => 15, 'profileUrl' => 'swag']],
    [['name' => 'Test', 'posts' => 3, 'profileUrl' => 'swag']],
    [['name' => 'Swaghetti', 'posts' => 34, 'profileUrl' => 'swag']],
];
// $data = json_decode($response, true);

usort($data, function($a, $b) {
    $a = array_column($a[0], 'posts');
    $b = array_column($b[0], 'posts');
    return ($a < $b) ? -1 : 1;
});

$slieced = array_slice($data, 0, 4);
foreach($slieced as $member) {
    if (is_array($member)) {
        foreach($member as $name) {
            echo '<p class="top-member-p">
                      <a href="'.$name['profileUrl'].'">'.ucfirst($name['name']).'</a> 
                      has '.$name['posts'] . ' posts
                  </p>'."\n";
        }
    }
}

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