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首页 > 解决方案 > 不能解决这个？你会如何解决这个问题？“条件中的变量绑定需要初始化程序”和“'if' 条件之后的预期 '{'”

swift - 不能解决这个？你会如何解决这个问题？“条件中的变量绑定需要初始化程序”和“'if' 条件之后的预期 '{'”

问题描述

标题总结了我的问题。我是编码新手，我不明白如何解决这个问题。

我已经尝试了几乎所有我知道的。

import UIKit
import AVKit
import AVFoundation

class ViewController: UIViewController {

    override func viewDidAppear(_ animated: Bool) {
        super.viewDidAppear(animated)
    }

    @IBOutlet weak var PowerLVLlabel: UILabel!

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view.

    }

    @IBAction func randomNumber(_ sender: Any) {

        let randomNumber = Int.random(in: 1000...10000)
        PowerLVLlabel.text = String(randomNumber)
        if case { randomNumber; >=9000 == (true);
            func playVideo() {
                guard let path = Bundle.main.path(forResource: "over 9000", ofType:"mp4") else {
                    debugPrint("over 9000.mp4 not found")
                    return
                }
                {let player = AVPlayer(url: URL(fileURLWithPath: path))
                let playerController = AVPlayerViewController()
                playerController.player = player
                    present(playerController, animated: true) }
                    {player.play()
}

标签： swift

解决方案

尝试这个：

func playVideo(){
    guard let path = Bundle.main.path(forResource: "over 9000", ofType:"mp4") else {
        debugPrint("over 9000.mp4 not found")
        return
    }
    let player = AVPlayer(url: URL(fileURLWithPath: path))
    let playerController = AVPlayerViewController()
    playerController.player = player
    present(playerController, animated: true)
    player.play()

}

@IBAction func randomNumber(_ sender: Any) {

        let randomNumber = Int.random(in: 1000...10000)
        PowerLVLlabel.text = String(randomNumber)

        if randomNumber >= 9000{
            playVideo()
        }
    }

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