swift - 在 TableViewCell 中加载图像

Question

我想将图像从 url 加载到 productimage，但我的代码不起作用。
如何将图像加载到tableViewCells?

public func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

    let cell = self.tableView.dequeueReusableCell(withIdentifier: "cellWomanSaved") as! WomanSavedTableViewCell

    let Data: DataModel

    Data = DataList[indexPath.row]

    cell.priceLabel.text = Data.Price
    cell.productLabel.text = Data.ImageURL
    cell.productImage.image = UIImage(data: url)

    if let url = URL(string: productLabel[indexPath.row]) {

        do {

            let data = try Data(contentsOf: url)
            self.swipeImage.image = UIImage(data: data)

        }catch let error {

            print(" Error : \(error.localizedDescription)")

        }
    }

    return cell
}

标签： swiftuitableview

Answer 1

• 在您的单元格中创建数据任务
• 在 prepareForReuse 函数中取消数据任务
• 将您的 url 传递给控制器​​ cellForRowAt 函数中的单元格

• 所以用模型填充你的单元格并将值设置为属性

  class MyCell: UITableViewCell {
  
      // MARK: - Outlets
  
      @IBOutlet weak var priceLabel: UILabel!
      @IBOutlet weak var productLabel: UILabel!
      @IBOutlet weak var productImage: UIImageView!
  
  
      /// create dataTask for cancel in prepareForReuse function
      private var dataTask: URLSessionDataTask?
  
      /// Like this
      override public func prepareForReuse() {
         super.prepareForReuse()
          dataTask?.cancel()
      }
  
      func populate(with model: YourModel) {
          priceLabel.text = model.Price
          productLabel.text = model.ImageUrl
  
          /// You should set url in indexPath of your logo array([ImageUrl])
          let url = model.ImageUrl /// It's sample url for explain this is an url of your current index model
          if let imageUrl = url {
              downloaded(from: imageUrl)
          }
      }
  
      func downloaded(from url: URL, contentMode mode: UIView.ContentMode = .scaleAspectFit) {
          contentMode = mode
          dataTask = URLSession.shared.dataTask(with: url) { data, response, error in
              guard
                  let httpURLResponse = response as? HTTPURLResponse, httpURLResponse.statusCode == 200,
                  let mimeType = response?.mimeType, mimeType.hasPrefix("image"),
                  let data = data, error == nil,
                  let image = UIImage(data: data)
                  else { return }
              DispatchQueue.main.async() {
                  self.productImage.image = image
              }
          }
          dataTask?.resume()
      }
  }
  

在控制器的 tableView cellForRowAt 函数中：

let model: DataModel = DataList[indexPath.row]
cell.populate(with: model)

return cell