python - 将一些 JSON 键转换为 Python 对象
问题描述
我有一个 Python 类,如下所示:
class Game:
"""Holds all game related attributes - usually one instance created per game."""
def __init__(
self,
game_id,
game_type,
date_time,
game_state,
venue,
home,
away,
preferred,
live_feed,
season,
):
self.game_id = game_id
self.game_type = game_type
self.date_time = date_time
self.game_state = game_state
self.venue = venue
self._live_feed = live_feed
self.home_team = home
self.away_team = away
self.season = season
目前,我通过从 API 响应解析 JSON 并挑选一些值并将它们传递给此类的init()
函数来创建此类的实例。
将 API 响应传递给init()
函数并从类中的 JSON 字典中解析/挑选这些属性以设置类级属性是否更好(所以围绕这个类的所有逻辑都在一个地方)?
例如,我在main()
函数中获取这些值,然后将它们传递给类。
# Create a Game Object
gameobj_game_id = game_info["gamePk"]
gameobj_game_season = game_info["season"]
gameobj_game_type = game_info["gameType"]
gameobj_date_time = game_info["gameDate"]
gameobj_game_state = game_info["status"]["abstractGameState"]
game_obj = Game(gameobj_game_id, gameobj_game_type, gameobj_date_time, gameobj_game_state...)
但是该代码是从对象创建逻辑中抽象出来的。
任何建议将不胜感激!
解决方案
您可能想要定义一个类方法,其工作是从此类响应中额外添加“正确”字段。
class Game:
"""Holds all game related attributes - usually one instance created per game."""
def __init__(
self,
game_id,
game_type,
date_time,
game_state,
venue,
home,
away,
preferred,
live_feed,
season,
):
self.game_id = game_id
self.game_type = game_type
self.date_time = date_time
self.game_state = game_state
self.venue = venue
self._live_feed = live_feed
self.home_team = home
self.away_team = away
self.season = season
@classmethod
def from_json(cls, resp):
return Game(
game_id=resp["gamePk"],
game_type=resp["gameType"],
...
)
类型本身是提供创建对象的规范方式的“方法”(Game(...)
间接等同于Game.__new__(...)
),不知道每一位信息的来源。其他类方法充当相同数据的各种来源的包装器。