android - 尝试输入 onDataChange Firebase Android 时应用程序崩溃
问题描述
我想在cardview中向我展示所有来自firebase数据库的用户,这些用户在recyclerview中,但在调试器中在UserActivity的第60行显示错误。我在我的数据库中放了一个截图:
用户片段:
public class UsersFragment extends Fragment {
private RecyclerView recyclerView;
private UserAdapter userAdapter;
private List<User> mUsers;
@Override
public View onCreateView (LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
// Inflate the layout for this fragment
View view= inflater.inflate ( R.layout.fragment_users3, container, false );
recyclerView=view.findViewById (R.id.recycler_view );
recyclerView.setLayoutManager ( new LinearLayoutManager ( getContext () ) );
mUsers=new ArrayList<> ( );
readUsers();
return view;
}
private void readUsers () {
final FirebaseUser firebaseUser= FirebaseAuth.getInstance ().getCurrentUser ();
DatabaseReference referenc= FirebaseDatabase.getInstance ().getReference ("users");
referenc.addValueEventListener ( new ValueEventListener () {
@Override
public void onDataChange (@NonNull DataSnapshot dataSnapshot) {
mUsers.clear ();
for(DataSnapshot snapshot:dataSnapshot.getChildren ()){
User user=snapshot.getValue (User.class);
assert user!=null;
assert firebaseUser!=null;
if(!firebaseUser.getUid ().equals ( user.getUid () )){
mUsers.add ( user );
}
}
userAdapter=new UserAdapter ( getContext (),mUsers );
recyclerView.setAdapter ( userAdapter );
}
@Override
public void onCancelled (@NonNull DatabaseError databaseError) {
}
} );
}
}
UserAdapter.In 我使用了 User 类:
public class UserAdapter extends RecyclerView.Adapter<UserAdapter.ViewHolder> {
private Context mContext;
private List<User> mUsers;
public UserAdapter(Context mContext,List<User> mUsers){
this.mUsers=mUsers;
this.mContext=mContext;
}
@NonNull
@Override
public ViewHolder onCreateViewHolder (@NonNull ViewGroup parent, int viewType) {
View view= LayoutInflater.from ( mContext ).inflate ( R.layout.users_template ,parent,false);
return new UserAdapter.ViewHolder ( view );
}
@Override
public void onBindViewHolder (@NonNull ViewHolder holder, int position) {
User user=mUsers.get ( position );
holder.username.setText ( user.getFirstName () );
}
@Override
public int getItemCount () {
return mUsers.size ();
}
public class ViewHolder extends RecyclerView.ViewHolder{
public TextView username;
public ViewHolder(View itemView){
super(itemView);
username=itemView.findViewById ( R.id.username1 );
}
}
}
存储 FirstName 的用户:
public class User {
public String firstName;
public String secondName;
public String uid;
public String email;
public User(){
}
public User (String firstName, String secondName, String uid, String email) {
this.firstName = firstName;
this.secondName = secondName;
this.uid=uid;
this.email=email;
}
public User (String firstname, String secondname) {
}
@PropertyName ( "FirsName" )
public String getFirstName () {
return firstName;
}
@PropertyName ("SecondName" )
public String getSecondName () {
return secondName;
}
@PropertyName ( "Uid" )
public String getUid () {
return uid;
}
@PropertyName ( "E-mail" )
public String getEmail () {
return email;
}
@PropertyName ( "FirsName" )
public void setFirstName (String firstName) {
this.firstName = firstName;
}
@PropertyName ( "SecondName" )
public void setSecondName (String secondName) {
this.secondName = secondName;
}
@PropertyName ( "Uid" )
public void setUid (String uid) {
this.uid = uid;
}
@PropertyName ( "E-mail" )
public void setEmail (String email) {
this.email = email;
}
}
我的数据库的规则是:
{
"rules": {
".read": "true",
".write":"true",
"users":{
"$user_id":{
".read": "auth.uid === $user_id",
".write": "auth.uid === $user_id"
}
}
}
}
在调试模式下,它向我显示:
E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.example.sportsbuddy, PID: 662
com.google.firebase.database.DatabaseException: Found two getters or fields with conflicting case sensitivity for property: secondname
at com.google.firebase.database.core.utilities.encoding.CustomClassMapper$BeanMapper.addProperty(com.google.firebase:firebase-database@@17.0.0:540)
at com.google.firebase.database.core.utilities.encoding.CustomClassMapper$BeanMapper.<init>(com.google.firebase:firebase-database@@17.0.0:471)
at com.google.firebase.database.core.utilities.encoding.CustomClassMapper.loadOrCreateBeanMapperForClass(com.google.firebase:firebase-database@@17.0.0:312)
at com.google.firebase.database.core.utilities.encoding.CustomClassMapper.convertBean(com.google.firebase:firebase-database@@17.0.0:413)
at com.google.firebase.database.core.utilities.encoding.CustomClassMapper.deserializeToClass(com.google.firebase:firebase-database@@17.0.0:214)
at com.google.firebase.database.core.utilities.encoding.CustomClassMapper.convertToCustomClass(com.google.firebase:firebase-database@@17.0.0:79)
at com.google.firebase.database.DataSnapshot.getValue(com.google.firebase:firebase-database@@17.0.0:212)
at com.example.sportsbuddy.Fragments.UsersFragment$1.onDataChange(UsersFragment.java:60)
at com.google.firebase.database.core.ValueEventRegistration.fireEvent(com.google.firebase:firebase-database@@17.0.0:75)
at com.google.firebase.database.core.view.DataEvent.fire(com.google.firebase:firebase-database@@17.0.0:63)
at com.google.firebase.database.core.view.EventRaiser$1.run(com.google.firebase:firebase-database@@17.0.0:55)
at android.os.Handler.handleCallback(Handler.java:873)
at android.os.Handler.dispatchMessage(Handler.java:99)
at android.os.Looper.loop(Looper.java:214)
at android.app.ActivityThread.main(ActivityThread.java:6986)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:493)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1445)
主要错误出现在 UsersFragment 中的 onDataChange 上。
我希望向我展示我在数据库中拥有的所有用户。
解决方案
你的错误说:
Found two getters or fields with conflicting case sensitivity for property: secondname
要了解此错误的含义,您需要了解 Firebase 如何对从数据库接收的数据进行序列化和反序列化。
Firebase 使用字段名称以及 getter 和 setter 来序列化和反序列化对象,这意味着,每当您从数据库接收 JSON 对象时,firebase 都会将这些键值与您的 getter/setter 以及 POJO 类中的字段进行映射。
要删除此错误,您必须更改字段名称,即
public String secondName;
与数据库中的内容不同,或者,您需要更改 getter 和 setter 函数名称。错误是因为 firebase 两次看到该属性,一次在您的字段中,第二次在您的 getter/setter 中。
另外,尝试将您的变量设为私有。它可能会有所帮助。另外,如何将数据库中的“电子邮件”更改为简单的“电子邮件”?
推荐阅读
- c# - 如何在 C# 中保留百分比单元格 NPOI 的数值
- python - 删除连续的重复值python
- jenkins - Jenkins 管道中 .yml 和 .groovy 文件之间的区别
- python - python日志模块跳过一些日志,不写入文件
- amazon-redshift - 我可以继续使用 Aginity Workbench 进行红移吗
- apache-spark - 如何以 JSON 格式转换 debezium 消息,以便可以将其加载到 Redshift
- azure-cosmosdb - Gremlin:CosmosDB Gremlin API 中 otherV 的替代方案
- spring - Spring JMS - IBM MQ MessagePutOptions
- excel - 使用 VBA 对多个工作簿求和,无需手动选择
- javascript - AJAX 请求未调用 python-flask 方法