时间戳

首页 > 解决方案 > Python UnboundLocalError：从字典中选择单词的函数出现问题

python - Python UnboundLocalError：从字典中选择单词的函数出现问题

问题描述

我编写了一个从字典中选择单个键（=word）的函数。如果该密钥已被使用，则应选择另一个密钥。这是我的功能：

nom_acc = {"qeso":"qes", "os":"os", "sondra":"sondre", "mawizzi":"mawizze", "khewo":"khewe", "alegra":"alegre", "kendra":"kendre", "zhalia":"zhalie", "achrakh":"achrakh", "ador":"ador", "hoggi":"hogge", "soqwi":"soqwe"}
usedWords = []

def wordChoice():
    global usedWords
    print(usedWords) ### DELETE LATER

    word = random.choice(list(nom_acc))     ### randomly pick a key from a dictionary (which is the nominative form)
    print(word) ### DELETE LATER 
    if word in usedWords: 
        print("gotta pick another word") ### DELETE LATER
        wordChoice() 
    else: 
        usedWords.append(word)          
        accusative = nom_acc[word]

    return word, accusative

该功能嵌入到主程序中。当我像这样运行代码时，只要选择了一个已经使用过的单词，它就会给我一条错误消息： UnboundLocalError: local variable 'accusative' referenced before assignment

如果我为单词和宾格变量添加一个虚拟值，它似乎可以工作：

    if word in usedWords: 
        print("gotta pick another word") ### DELETE LATER
        word="DUMMY"
        accusative="DUMMY"

但我想要的是，如果该词已被使用，则从字典中选择另一个词。我该如何实施？

标签： pythonfunctiondictionaryif-statementrandom

解决方案

这是调用 wordChoice() 函数的代码部分：

def writeAcc():
    '''Minigame: User has to enter the correct accusative form, after three correct answers he passed'''

    global isPlaying, usedWords
    isPlaying = True

# asking the user to enter the right accusative form of the word        
    print("Please enter the accusative form of the following words\n")

# player passed when he reached 3 correct answers
    right = 0
    while right < 4:
        word, accusative = wordChoice()

        print("Nominative ", word)

        print("Need help? Enter 'y' to see the menu again or press the enter-key to continue.")
        choice = input("\t\t\tChoice: ")
        if choice == 'y':
            continueGame = displayMenu()
            if not continueGame:
                return
            print("Nominative ", word)

        answer=input("Accusative ")
        if answer==accusative:
            right+=1

        print("Guessed right:", right)

        if right < 4 and (len(usedWords) == len(list(nom_acc))):
            print("Sorry you don't seem to have what it takes to learn the accusative.")
            break

    if right == 4:
        print("Congratulations! You passed the first step, you will now enter the next challenge.")

推荐阅读